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vovikov84 [41]
3 years ago
12

Name an event that would be measured in days

Mathematics
2 answers:
telo118 [61]3 years ago
8 0
Well, things like sporting events, or freak storms are measured in days, or weeks. Depends. For weather, it could be hurricanes, tornado's, or even large fires(not quite weather, but could be)
GrogVix [38]3 years ago
8 0
Sporting events

tour de france
world cup
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12x - 16 = 68<br> Solve for x
cricket20 [7]

Answer:

x = 7

Step-by-step explanation:

12x - 16 = 68

Add 16 to each side

12x - 16+16 = 68+16

12x =84

Divide by 12

12x/12 = 84/12

x = 7

6 0
3 years ago
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This is pre calculus please help !Describe three ways to determine the measure of segment YZ.
Dmitry [639]
(1) Using trigonometric ratios:
sin(30) = \frac{YZ}{50}
YZ = 25

(2) Using Pythagoras' Theorem:
cos(30) = \frac{XY}{50}
50cos(30) = XY
50^{2} - 50^{2}cos^{2}(30) = YZ^{2}
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(3) Using sine rule:
\frac{50}{sin(90)} = \frac{YZ}{sin(30)}
50 = \frac{YZ}{sin(30)}
50sin(30) = YZ
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7 0
3 years ago
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What is the answer and how do you solve <br><br><br> 21x^3/3x^−1
Sunny_sXe [5.5K]

Answer:

  as written: 7x^2

  perhaps intended: 7x^4

Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

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___

Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

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then the simplification is ...

  \dfrac{21x^3}{3x^{-1}}=\dfrac{21}{3}x^{3-(-1)}=7x^4

_____

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^b/a^c = a^(b-c)

6 0
3 years ago
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lisabon 2012 [21]
8%

$5.60 x 100/ 70 = 8
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3 years ago
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lorasvet [3.4K]
In order to find b1 from your formula stated we need to do few calculations
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I will subtract hb2 from both sides
hb1=A-hb2
now I will divide my new expression by h
b1=(A-hb2)/h
8 0
3 years ago
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