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crimeas [40]
2 years ago
15

Algebra solve each equation (30 points)

Mathematics
2 answers:
Hitman42 [59]2 years ago
8 0
They all 3 have no solution!
Aneli [31]2 years ago
6 0

Answer:

Look below

Step-by-step explanation:

Note: i=\sqrt{-1}

18. Start by factoring out a 5 on the left side:

5(x^2+25)=0

Then, divide both sides by 5:

x^2+25=0

Subtract 25 from both sides:

x^2=-25

Take the square root of both sides:

x=-\sqrt{-25}  \ or\ x=-\sqrt{25}

x=-5i, 5i

20. Start by adding 16 to both sides:

-x^2=16

Divide both sides by -1:

x^2=-16

Take the square root of both sides:

x=-\sqrt{16} \ or\ -\sqrt{-16}

x=-4i, 4i

22. Start by subtracting 96 from both sides:

8x^2=-96

Divide both sides by 8:

x^2=-12

Take the square root of both sides:

x=\sqrt{-12}\ or\ -\sqrt{-12}

x=-2i\sqrt{3}, 2i\sqrt{3}

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matrenka [14]

Given:

In trapezoid ABCD, AD\parallel BC, MN is the mid-segment of ABCD, AD=30x-10,MN=31x+1,BC=30x+28.

To find:

The length of AD.

Solution:

We know that the length of the mid-segment of a trapezoids is half of the sum of lengths of two parallel sides of the trapezoid.

In trapezoid ABCD,

MN=\dfrac{AD+BC}{2}

31x+1=\dfrac{30x-10+30x+28}{2}

31x+1=\dfrac{60x+18}{2}

31x+1=30x+9

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31x-30x=9-1

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Now,

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AD=30(8)-10

AD=240-10

AD=230

Therefore, the length of AD is 230.

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