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deff fn [24]
3 years ago
13

A certain medicine is given in an amount proportional to a patient's body weight. Suppose a patient weighing 104 pounds requires

169 milligrams of medicine. What is the weight of a patient who requires 224.25 milligrams of medicin
Mathematics
1 answer:
Olegator [25]3 years ago
8 0
104 / 169 = x / 224.25......104 lbs to 169 mg = x lbs to 224.25 mg
cross multiply because this is a proportion
(169)(x) = (104)(224.25)
169x = 23322
x = 23322 / 169
x = 138 lbs <==
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Jada have a monthly budget for her cell phone bill last month she spent 120% of her budget and the bill was $60 what is Jada mon
Damm [24]

Assume that the budget is n.

Now we are given that 120% of the budget is equal to $60.

This means that:

60 = 1.2n

Solve the equation for n to know the budget:

60 = 1.2n

n = 60 / 1.2 = 50

Based on the above calculations, Jada's budget is 50$

4 0
2 years ago
Read 2 more answers
Jose has completed 6 deliveries so far this week. He needs to make 40 deliveries for the week. What percentage of his deliveries
ANEK [815]
Yes 10? 11x1x6= 26 hbu the first one to the end of a century
8 0
2 years ago
May I please get help. ​
Karo-lina-s [1.5K]

Answer:

y = -\frac{2}{3} +6

Step-by-step explanation:

To be parallel to the original line, the slope has to be the same (-\frac{2}{3}). For the line to go through the point (6,2) the y-intercept has to be 6.

The graph shows the original line (black) and new line that goes through the point (yellow).

Hope it helps!

3 0
2 years ago
Plzz help me solve questions 15 and 16...!!
iVinArrow [24]

15.

We have right triangles, with the ladder the hypotenuse of both and the wall the opposite side of both.

Call the ladder length <em>h.</em>

Against the wall we have the opposite of alpha the taller one:

q = h \sin \alpha - h \sin \beta

On the ground adjacent to beta is the longer one

p = h \cos \beta - h \cos \alpha

Dividing

\dfrac p q = \dfrac{  h \cos \beta - h \cos \alpha }{h \sin \alpha - h \sin \beta} =  \dfrac{ \cos \beta -\cos \alpha }{\sin \alpha - \sin \beta} \quad\checkmark

16.

Again I'm too lazy to draw the figure but you should.

Let's call <em>y </em>the height of the tower and <em>x</em> the distance from the observation point on the ground to the base of the tower.

\tan 60^\circ = \dfrac y x

\tan 30^\circ = \dfrac{y - 40}{x}

Since \sin 30 =\cos 60 = \frac 1 2 \textrm{ and } \cos 30 = \sin 60 = \sqrt{3}/2

\tan 60^\circ = \sqrt{3} = y/x

\tan 30^\circ = 1/\sqrt{3} = (y-40)/x

Dividing,

\sqrt{3}/ (1/\sqrt{3}) = (y/x) / ((y-40)/x)

3 = y/(y-40)

3y - 120 = y

2y = 120

y = 60

x = y/\sqrt{3} = 60(\sqrt{3}/3) = 20 \sqrt{3}

Answer: Height 60 meters, distance 20√3 meters

5 0
3 years ago
Can two lines that have the same slope and Y intercept have no solution
lianna [129]

Answer:

  no (or maybe)

Step-by-step explanation:

NO:

Two lines with the same slope and y-intercept will be identical lines. Every point that satisfies one equation will also satisfy the other, so there will be an infinite number of solutions. (not <em>no solution</em>)

__

MAYBE:

If those two lines are part of a larger system that includes parallel lines (or non-intersecting curves), then that larger system will have <em>no solution</em>.

5 0
3 years ago
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