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2 years ago

10

Right and solve multiplication equations

2 answers:

IgorLugansk [536]2 years ago

7 0

Answer:

45

Step-by-step explanation:

$15 = \frac{1}{3} x \\ 15 \times 3 = x \\ x = 45$

WITCHER [35]2 years ago

6 0

Answer:

45

Step-by-step explanation:

Divide both sides by 3

then it will be X=15×3

. =45

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Lauren is shopping and finds 6 bracelets, 2 pairs of earrings, and 3 necklaces that she likes. How many ways can Lauren select 4

Grace [21]

Because it does not specify that she has to choose one or two from each category all pieces of jewelry can be treated as choices in a combination set.

the formula for a combination is

$C(n,r)= \frac{n!}{r!(n-r)!}$

where n is a total number of choices ( 11 )
and r is number chosen out of those choices (4)
so

C(11,4)= \frac{11!}{4!(11-4)!}

She has 330 possible choices to come home with 4 pieces of jewelry

5 0

3 years ago

Read 2 more answers

Solve for x in the following equation.

KonstantinChe [14]

Hello,

$3 {}^{a} = 3 {}^{b} \Leftrightarrow \: a = b$

$3 {}^{x} = {3}^{2} \Leftrightarrow \: x = 2$

5 0

2 years ago

NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.

slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

$\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2$

<u>Total Surface Area</u>

Area of the isosceles triangle:

$\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2$

Total surface area:

$\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)$

<u>Volume</u>

$\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)$

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

$\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2$

<u>Total Surface Area</u>

Area of a pentagon:

$\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2$

where a is the side length.

Therefore:

$\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)$

Total surface area:

$\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)$

<u>Volume</u>

$\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)$

8 0

2 years ago

A. 0.333<br> B. 6<br> C. 0.667<br> D. 3

kow [346]

c

Answer:

Step-by-step explanation:

8 0

3 years ago

Polygon ABCD is a przimage of an enlargement with a scale factor of 3 and a

Flura [38]

i dont think you have a whole question down and we need examples of the triangles so please shw examples

4 0

3 years ago