How do I figure out what the measure of Angel ABC ?
1 answer:
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Answer:
Let the vectors be
a = [0, 1, 2] and
b = [1, -2, 3]
( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.
Let the cross product be another vector c.
To find the cross product (c) of a and b, we have
c = i(3 + 4) - j(0 - 2) + k(0 - 1)
c = 7i + 2j - k
c = [7, 2, -1]
( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:
c / | c |
Where | c | = √ (7)² + (2)² + (-1)² = 3√6
Therefore, the unit vector is
or
[ ,
,
]
The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:
[ ,
,
]
In conclusion, the two unit vectors are;
[ ,
,
]
and
[ ,
,
]
<em>Hope this helps!</em>
Answer:
see attached
Step-by-step explanation:
Each digit of the quotient is aligned with the least significant digit of the current dividend. The "current dividend" is that portion of the remaining dividend that is at least 1 and less than 10 times the divisor. The product of the quotient digit and the divisor is subtracted from the "current dividend" to get the remaining dividend.
__
For many folks, the hardest part of this algorithm is determining the appropriate quotient digit, and multiplying that by the divisor. Some teachers teach that you start this process by making a list of the multiples of the divisor:
N . . . 28N
1 28
2 56
3 84
4 112
...
This process can be aided by your number sense.
2N is simply N added to itself.
3N is N+2N.
4N is double 2N
5N is half of 10N.
You can proceed to build the table by adding 28 to each previous value, or by recognizing doubles and halves and other sums.
