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Advocard [28]
3 years ago
12

Use area model to explain the product 4.6 and 3. Write the product in standard form, word form and expanded form.

Mathematics
2 answers:
kenny6666 [7]3 years ago
4 0
Use area model to explain the product and 4.6 3. Write the product in standard form, word form and expanded form. 
 Standard form: 4.6     3 
 Word form: 4.0 + 0.6    3
<span>expanded form: four point six      three</span>
enyata [817]3 years ago
3 0

Answer: Product = 13.8

Step-by-step explanation:

<u>As we have to use area model :</u>

So, we

Let length of rectangle be 4.6

Let breadth of rectangle be 3

As we know that

Area of rectangle is given by

Length \times breadth\\\\=4.6\times 3\\\\=13.8\text{ squared units }

Now, we must write in standard form, word form and expanded form:

So,

Standard form = 13.8

Word form = thirteen and 8 tenths

Expanded form is given by

13.8=1\times 10+3\times 1+8\times \frac{1}{10}

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6 0
3 years ago
Read 2 more answers
What is the seventh term of (x + 4)8?
Arisa [49]
The (p+1)-th term of the Newton binomial expansion

(a+b)^{n}

is given by

t_{p+1}=\dbinom{n}{p}\,a^{n-p}\,b^{p}
__________________________

We want the 7th term. Hence, we set p+1 to be 7:

p+1=7~~\Rightarrow~~p=6


Then, the 7th term is

t_{7}=\dbinom{8}{6}\,x^{8-6}\,4^{6}\\\\\\ t_{7}=\dfrac{8!}{6!\cdot (8-6)!}\cdot x^{8-6}\cdot 4^{6}\\\\\\ t_{7}=\dfrac{8\cdot 7\cdot \diagup\!\!\!\! 6!}{\diagup\!\!\!\! 6!\cdot 2!}\cdot x^{2}\cdot 4^{6}\\\\\\ t_{7}=\dfrac{8\cdot 7}{2\cdot 1}\cdot x^{2}\cdot 4^{6}\\\\\\ t_{7}=28\cdot x^{2}\cdot 4,096\\\\ \boxed{\begin{array}{c} t_{7}=114,688\,x^{2} \end{array}}


Correct answer: \text{A. }114,688\,x^{2}.

8 0
4 years ago
Grandma is baking 108 cookies. How many cups of sugar will she need?
NeX [460]

Answer:

Step-by-step explanation:

3 0
3 years ago
The product of eight and the sum of a number and nine
Crazy boy [7]
8(n + 9) <== ur expression
8 0
3 years ago
Find all real numbers t such that (2/3)t - 1 &lt; t + 7 ≤ -2t + 15. Give your answer as an interval.
Andrews [41]
Break up chain with AND statement:

(2/3)t - 1 < t + 7 AND <span>t + 7 ≤ -2t + 15

left side, we solve for t
</span>
<span>(2/3)t - 1 < t + 7
(2/3)t - t < 7 + 1
(-1/3)t < 8
t > -24

right side, we solve for t</span>
<span>t + 7 ≤ -2t + 15
t + 2t </span><span>≤ 15 - 7
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t </span><span>≤ 8/3

So our answer would be </span>
t > -24 AND t <span>≤ 8/3

as an interval, this is
</span>-24 < t <span>≤ 8/3
or in interval notation
(-24, 8/3]</span>
8 0
4 years ago
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