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ELEN [110]
2 years ago
13

John's father has a large collection of ties. He has 20 ties, and 8 of them are pink.

Mathematics
2 answers:
Eva8 [605]2 years ago
8 0

Answer:

57.77% out of 100

john's father would pick pink because pink is in less number

AlladinOne [14]2 years ago
5 0

Answer:

25%

Step-by-step explanation:

20 divided by 8 times 100 take away the zero

percentage = part/whole x 100

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4 0
3 years ago
Read 2 more answers
Your mission is to dilate the rectangle shown below by a scale factor of 2.
yawa3891 [41]

Answer:

The dimensions of the dilated rectangle are 30 cm x 16 cm

Step-by-step explanation:

we know that

To find the dimensions of the dilated rectangle, multiply the original dimensions by the scale factor

so

Let

A'B'C'D'------> the dilated rectangle

z-------> the scale factor

we have

z=2

A'B'=AB*z=15*2=30 cm

B'D'=BD*z=8*2=16 cm

The dimensions of the dilated rectangle are 30 cm x 16 cm

6 0
4 years ago
Which equation correctly demonstrates the distributive property?
kondaur [170]

Answer:

C.

Step-by-step explanation:

This equation is properly distributed. 6×4=24 and 6×-3w= -18w. the equation becomes 24-18w

6 0
3 years ago
Read 2 more answers
4. According to statistics reported on IN-CORP a surprising number of motor vehicles are not covered by insurance. Sample result
son4ous [18]

Answer:

a) 0.23

b) The 95% confidence interval for the population proportion is (0.1717, 0.2883).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Point estimate

The point estimate is:

\pi = \frac{46}{200} = 0.23

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.23 - 1.96\sqrt{\frac{0.23*0.77}{200}} = 0.1717

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.23 + 1.96\sqrt{\frac{0.23*0.77}{200}} = 0.2883

The 95% confidence interval for the population proportion is (0.1717, 0.2883).

5 0
3 years ago
Help me with this!! I will mark Brainliest!!!
user100 [1]

Answer:

1...-

Step-by-step explanation:

7 0
3 years ago
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