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Aleksandr [31]
4 years ago
10

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Mathematics
1 answer:
san4es73 [151]4 years ago
4 0
Lol I’m confused???????
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Can someone smart help me with this plz:)
insens350 [35]

Answer:

Step-by-step explanation:

Sum of all angles of triangle = 180°

6p + 6p + 3 p = 180

15p = 180

p = 180/15

p = 12

Angles are:

6p = 6*12 = 72°

3p = 3*12 = 36°

Angles are: 72°, 72° , 36°

6 0
4 years ago
A circle has a radius of 5 in. A central angle that measures 150° cuts off an arc.
Slav-nsk [51]

Answer:

Part 1) The exact value of the arc length is \frac{25}{6}\pi \ in

Part 2) The approximate value of the arc length is 13.1\ in

Step-by-step explanation:

step 1

Find the circumference of the circle

The circumference of a circle is equal to

C=2\pi r

we have

r=5\ in

substitute

C=2\pi (5)

C=10\pi\ in

step 2

Find the exact value of the arc length by a central angle of 150 degrees

Remember that the circumference of a circle subtends a central angle of 360 degrees

by proportion

\frac{10\pi}{360} =\frac{x}{150}\\ \\x=10\pi *150/360\\ \\x=\frac{25}{6}\pi \ in

step 3

Find the approximate value of the arc length

To find the approximate value, assume

\pi =3.14

substitute

\frac{25}{6}(3.14)=13.1\ in

7 0
3 years ago
If the equation of the line is y=-5.9x+91.9 . Which statement is false?
solong [7]

Answer:

. The slope of the line indicates that test score and the time spent watching tv are negatively correlated

5 0
3 years ago
Plz help<br> Don’t know which one it is?
ddd [48]

Answer:

 First option  6^\frac{1}{6} is the correct answer.

Step-by-step explanation:

Let us consider each part, we have number 6 inside all the roots.

First we have to find cube root of 6.

                    \sqrt[3]{6} =6^\frac{1}{3}

Now we have to find square root of this value.

                   \sqrt{6^\frac{1}{3}  } =(6^\frac{1}{3} )^\frac{1}{2} =6^\frac{1}{6}

So, first option  6^\frac{1}{6} is the correct answer.

3 0
3 years ago
Please tell me the answer quick
fomenos

Answer:

D) The expression 9 - p has exactly 2 terms

8 0
3 years ago
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