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Aleksandr [31]
4 years ago
10

Jwdfkjasnfjasdhfokjasfnhj asjdnajskd

Mathematics
1 answer:
san4es73 [151]4 years ago
4 0
Lol I’m confused???????
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Factor the expression. 48g2 – 22gh – 15h2
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It’s B because it’s the right answer
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Janet had a sheet of paper tht was 4 inches long and the area was 40 inches.what is the witdth of paper
pav-90 [236]
4 * width = 40
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3 years ago
Which is a step in the process of calculating successive discounts of 8% and 10% on a $50 item
Paraphin [41]

Answer:

The  process of calculating successive discounts of 8% and 10% on a $50 item is take 10% of $46.

Step-by-step explanation:

As given

successive discounts of 8% and 10% on a $50 item .

First find out for 8 % discount

8% is written in the decimal form

= 0.08

8 % of $50 item = 0.08 × 50

                          = $ 4

Price of item after 8% discount = 50 - 4

                                                    = $46  

First find out for 10 % discount

10% is written in the decimal form

= 0.1

8 % of $48 item = 0.1× 46

                          = $4.6

Price of item after 8% discount = 46 - 4.6

                                                    = $41.4

Therefore in the successive discounts of 8% and 10% on a $50 item is $41.4 .

5 0
3 years ago
Help please. I need this in a few minutes
Ghella [55]

Answer:

Step-by-step explanation:

6 0
3 years ago
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How do I solve these problems? ln(x) = 5.6 + ln(7.5) and log(x) = 5.6 - log(7.5)
SOVA2 [1]

Use the rules of logarithms and the rules of exponents.

... ln(ab) = ln(a) + ln(b)

... e^ln(a) = a

... (a^b)·(a^c) = a^(b+c)

_____

1) Use the second rule and take the antilog.

... e^ln(x) = x = e^(5.6 + ln(7.5))

... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents

... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms

... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)

2) Similar to the previous problem, except base-10 logs are involved.

... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.

... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5

... x ≈ 53,080.96

8 0
3 years ago
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