Given line bd is a perpendicular bisector of ac prove triangle abc is isoscles.

180 lb 12 oz - 79.3 kg = ___________ kg

Brrunno [24]

Answer:

$180lb\ 12 oz - 79.3kg = 2.8kg$

Step-by-step explanation:

Given

$180\ lb 12\ oz - 79.3kg$

Required

Solve

First, convert 180lb to kg

$1lb \to 0.454kg$

$180lb \to 180 *0.454kg$

$180lb \to 81.7kg$ -- to 1dp

Next, convert 12oz to kg

$1oz \to 0.03kg$

$12oz \to 12 * 0.03kg$

$12oz \to 0.4kg$ --- to 1 dp

So, the expression becomes:

$180\ lb 12\ oz - 79.3kg$

$81.7kg + 0.4kg - 79.3kg$

$= 2.8kg$

Hence:

$180lb\ 12 oz - 79.3kg = 2.8kg$

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cint%20%5Cfrac%7Bdx%7D%7Bxln%5E%7Bp%7Dx%20%7D" id="TexFormula1" title=" \int \frac{dx}{xl

Eva8 [605]

Substitute $u=\ln x$ , so that $\mathrm du=\dfrac{\mathrm dx}x$ . The integral is then equivalent to

$\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\int\frac{\mathrm du}{u^p}=\begin{cases}\dfrac{u^{p+1}}{p+1}+C&\text{for }p\neq1\\\\\ln|u|+C&\text{for }p=1\end{cases}$

Then transforming back to $x$ gives

$\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\begin{cases}\dfrac{\ln^{p+1}x}{p+1}+C&\text{for }p\neq1\\\\\ln|\ln x|+C&\text{for }p=1\end{cases}$

4 0

3 years ago

Can u help me with this full sheet of work

nadezda [96]

Sometimes it takes a while to learn them but youll get it:)
1. she
2. they
3. him
4. she
5. them
6. it
7. Nate, he
8. Juwon, him
9. the sky, it
10. Mrs. P, her
11. a great catch, it
12. the coach, his OR new players, they

6 0

2 years ago

Read 2 more answers

If you could body swap with any person for 24 hours, who would you choose?

Anastasy [175]

Answer:

Chris evans

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Marcus loves baseball and wants to create a home plate for his house. Marcus needs to calculate the area of the home plate at th

Jobisdone [24]

Answer:

Area of the polygon = 59 in²

Explanation:

From the given diagram, we can note that the given polygon is composed of an upper triangle, a side triangle and a rectangle

Therefore:

Area of polygon =

area of upper triangle + area of side triangle + area of rectangle

1- getting the area of the upper triangle:

We have:

base of triangle = 7 in

height of triangle = 6 in

Therefore:

Area of upper triangle = $\frac{1}{2}*base*height = \frac{1}{2}*7*6=21$ in²

2- getting the area of the side triangle:

We have:

base of triangle = 4 in

height of triangle = 5 in

Therefore:

Area of upper triangle = $\frac{1}{2}*base*height = \frac{1}{2}*4*5=10$ in²

3- getting the area of the rectangle:

We have:

length of rectangle = 7 in

width of rectangle = 4 in

Therefore:

Area of rectangle = length x width = 7 x 4 = 28 in²

4- getting the total area of the polygon:

Area of polygon =

area of upper triangle + area of side triangle + area of rectangle

Therefore:

Area of polygon = 21 + 10 + 28 = 59 in²

Hope this helps :)

4 0

3 years ago