The value of f⁻¹(f(58)) is 58 and the value of the function f(f(5)) is 11
<h3>How to solve the function values?</h3>
As a general rule, we have:
f⁻¹(f(x)) = x
Substitute 58 for x
So, we have:
f⁻¹(f(58)) = 58
Hence, the value of f⁻¹(f(58)) is 58
Also, we have:
f(f(5))
From the table, we have:
f(5) = 9
So, we have:
f(f(5)) = f(9)
From the table, we have:
f(9) = 11
So, we have:
f(f(5)) = 11
Hence, the value of the function f(f(5)) is 11
Read more about invertible function at:
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Answer: any neative number thats -16 and up
for example -16, -17,-18 etc
Step-by-step explanation:
89 squared minus 39 squared and the answer you get is what you put into the radical
Answer:
B
Step-by-step explanation:
2x-5y=13.........(1) × 3
-3x+2y=13.......(2) × 2
6x - 15y = 39
-6x + 4y = 26
Adding
6x - 6x - 15y + 4y = 13 + 13
I suppose you mean
Then
and the difference quotient is
If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with
