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Lisa [10]
3 years ago
11

Please help me with this question !

Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer:

y=1x+1 is your answer

Step-by-step explanation:

you find the slope and y-int

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\bf csc(\theta)=\cfrac{1}{sin(\theta)}
\\\\\\
sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})\\\\
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\bf \cfrac{\sqrt{2}}{2}\cdot \cfrac{\sqrt{3}}{2}-\cfrac{\sqrt{2}}{2}\cdot \cfrac{1}{2}\implies \cfrac{\sqrt{6}}{4}-\cfrac{\sqrt{2}}{4}\implies \cfrac{\sqrt{6}-\sqrt{2}}{4}\\\\
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and now, we can rationalize the denominator by using its conjugate and difference of squares.

\bf \cfrac{4}{\sqrt{6}-\sqrt{2}}\cdot \cfrac{\sqrt{6}+\sqrt{2}}{\sqrt{6}+\sqrt{2}}\implies \cfrac{4(\sqrt{6}+\sqrt{2})}{(\sqrt{6}-\sqrt{2})(\sqrt{6}+\sqrt{2})}
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\cfrac{4(\sqrt{6}+\sqrt{2})}{(\sqrt{6})^2-(\sqrt{2})^2}\implies \cfrac{4(\sqrt{6}+\sqrt{2})}{6-2}\implies \boxed{\sqrt{6}+\sqrt{2}}
6 0
3 years ago
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