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Lady bird [3.3K]
3 years ago
6

Match each step with the property used to get to that step. (Note: the column that lists the algebraic expressions is already in

the correct order.)
(6x+3)-5x


1.(3+6x)-5x. Commutative
2. 3+(6x-5x). Multiplicative identity.
3. 3+(6-5)x. Associative
4. 3+(1)x. Subtraction
5. 3+x. Distributive


I WILL MARK BRAINLIEST
Mathematics
2 answers:
Romashka [77]3 years ago
8 0

Answer:

Commutative property:

a+b= b+a for any a and b

Multiplicative identity:

a \cdot 1 = 1 \cdot a for any a.

Associative property:

a+(b+c) = (a+b)+c for any a, b and c

Distributive property:

a \cdot (b+c) = a\cdot b+ a\cdot c

Given the equation:

(6x+3)-5x

1.

Using commutative property:

(3+6x)-5x

2.

Using associative property.

3+(6x-5x)

3.

Using distributive property:

3+(6-5)x

4.

using subtraction.

3+(1)x

5.

Using Multiplicative identity:

3+x

Now, match each step with the property used to get to that step are as follow:

1. (3+6x)-5x           [Commutative property]

2. 3+(6x-5x)           [Associative property]

3. 3+(6-5)x             [Distributive property]

4.  3+(1)x                  [Subtraction]

5. 3+x                     [Multiplicative property]

Norma-Jean [14]3 years ago
7 0
(6x + 3) - 5x

(3 + 6x) - 5x.....commutative
3 + (6x - 5x).....associative
3 + (6 - 5)x...distributive
3 + 1x....subtraction
3 + x....multiplicative identity
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For the set X = {a, b, c}, the following three relations satisfy the required conditions in (a), (b) and (c) respectively.

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(b) R = {(a, a), (b, b), (c, c), (a, b)} is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)} is symmetric and transitive but not reflexive .

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Given a relation R on a set X,

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R is said to be symmetric if for every (a, b) \in R, (b, a) \in R.

R is said to be transitive if (a, b) \in R and (b, c) \in R, then (a, c) \in R.

(a) Let R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)}.

Reflexive: (a, a), (b, b), (c, c) \in R

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Symmetric: (a, b) \in R \implies (b, a) \in R

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Transitive: (a, b) \in R \ and \ (b, c) \in R but but (a,c) is not in  R.

Therefore, R is not transitive.

Therefore, R is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)}

Reflexive: (a, a), (b, b) \ and \ (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \ but \ (b, a) \not \in R

Therefore R is not symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)}

Reflexive: (a, a) \in R but (b, b) and (c, c) are not in R

R must contain all ordered pairs of the form (x, x) for all x in R to be considered reflexive.

Therefore, R is not reflexive.

Symmetric: (a, b) \in R and (b, a) \in R

Therefore R is symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

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