Let x be the number on the first bus.
The distribution of students is x + (x +4) + (x + 4 + 9) = 167
3x + 17 = 167
3x = 167 - 17 = 150
The number on the first bus x = 50
The number on the second bus = 54
The number on the third bus = 63
<em>Complementary </em>angles are two angles that add up to a <em>right </em>angle, or 90°.
If ∠A and ∠B are complementary, that means that m∠A + m∠B = 90°. Plugging in the given values for m∠A and m∠B, we have
(2x-29) + (x + 23) = 90
Which we can use to solve for x:
2x - 29 + x + 23 = 90
(2x + x) + (-29 + 23) = 90
3x - 6 = 90
3x = 96
x = 32
Since we already know m∠B = (x + 23)°, we can substitute x to find that m∠B = (32 + 23)° = 55°
Answer:
42
Step-by-step explanation:
g(4) = 2x^2+5
= 2(4)^2+5
= 2(16)+5
= 32+5
= 37
f(g(4)) = 21+3sqrt(x+12)
= 21+3sqrt(37+12)
= 21+3sqrt(49)
= 21+3(7)
= 21+21
= 42
Answer:
15
Step-by-step explanation: