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egoroff_w [7]
2 years ago
12

Are these triangles similar triangles?

Mathematics
2 answers:
Eddi Din [679]2 years ago
5 0

Answer:

Yes, they are similar according to Angle Side Angle postulate.

Step-by-step explanation:

Zanzabum2 years ago
3 0
A. Angle side angle
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Find the value of sin T rounded to the nearest hundredth, if necessary.
katovenus [111]
<h3>Answer:  0.6</h3>

========================================

Work Shown:

sin(angle) = opposite/hypotenuse

sin(T) = VU/VT

sin(T) = 3/5

sin(T) = 0.6

6 0
2 years ago
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What os the correct question and why​
mr_godi [17]

Answer:

maybe the second equation i.e(10+1.2)x=24

8 0
2 years ago
Jacob is a teacher. He made 75 cookies to give to his students on the first day of school. He gave 2 cookies to each student who
Lisa [10]

Answer:

See explanation

Step-by-step explanation:

Jacob has 75 cookies.

He gave 2 cookies to each student.

Complete the table:

\begin{array}{cc}\text{Number of student arrived}&\text{Number of cookies left}\\1&75-2=73\\2&73-2=71\\3&71-2=69\\...&...\end{array}

Let n be the number of students. After nth student arrived Jacob had left

g(n)=75-2n

cookies.

This is an arithmetic sequence with

g_1=g(1)=73\\ \\d=-2

Thus,

g_{n}=g_{n-1}-2\\ \\g(n)=g(n-1)-2

3 0
3 years ago
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Which of the equations below could be the equation of this parabola?
nirvana33 [79]

Answer:

 y=-4x^2  is the equation of this parabola.

Step-by-step explanation:

Let us consider the equation

y=-4x^2

\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)

As

\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)

\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}

y=-4x^2

\mathrm{The\:parabola\:params\:are:}

a=-4,\:m=0,\:n=0

x_v=\frac{m+n}{2}

x_v=\frac{0+0}{2}

x_v=0

\mathrm{Plug\:in}\:\:x_v=0\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}

y_v=-4\cdot \:0^2

y_v=0

Therefore, the parabola vertex is

\left(0,\:0\right)

\mathrm{If}\:a

\mathrm{If}\:a>0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}

a=-4

\mathrm{Maximum}\space\left(0,\:0\right)

so,

\mathrm{Vertex\:of}\:-4x^2:\quad \mathrm{Maximum}\space\left(0,\:0\right)

Therefore,  y=-4x^2  is the equation of this parabola. The graph is also attached.

7 0
3 years ago
Read the following excerpt from a personal narrative essay. Based on the excerpt, what did the writer learn from her personal ex
Tresset [83]
The best answer is b
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3 years ago
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