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MA_775_DIABLO [31]
2 years ago
13

Find the x then slove, please help I tried already and I can't find it

Mathematics
1 answer:
Elena L [17]2 years ago
3 0

Answer:

8.4

Step-by-step explanation:

The diagonals of a rectangle are equal.

That means WY = XZ

16x+2 = 36x-6

Subtract 16x from each side.

16x -16x+2 = 36x-16x-6

2 = 20x -6

Add 6 to each side

2+6 = 20x-6+6

8 = 20x

Divide by 20

8/20 = 20x/20

2/5 =x

We want to find the length of the diagonal

WY = 16 ( 2/5) +2

Changing to decimal form

WY =16 * .4 +2

WY =6.4+2

     = 8.4

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Find the surface area of the pyramid. The side lengths of the base are equal. Square pyramid with base edge of 12 centimeters, a
sdas [7]

Answer:

the surface area of the square pyramid is 576.66 cm^2

Step-by-step explanation:

The computation of the surface area of square pyramid is given below:

A = a^2  + 2a × √a^2 ÷ √4 + √h^2

where

a = 12 cm

h = 17 cm

Now put the value of a and h in the above formula

= 12^2 + 2(12) × √12^2 ÷ √4 + √17^2

= 576.66 cm^2

hence, the surface area of the square pyramid is 576.66 cm^2

8 0
2 years ago
Find the total number of unit cube that fill the entire prism
Nonamiya [84]

Answer:

72 cubes

Step-by-step explanation:

Attached is the picture drawn (though not great one), showing 6 cube on length of prism, 3 cubes on width and 4 cubes on height of prism.

Given: Length of prism= 6

           Width= 3

            Height= 4

To know the number of cubes, which can fill the entire prism, we need to find volume of prism.

∴ Volume of prism= length\times width\times height

Volume of prism= 6\times 3\times 4= 72

∴ 72 units of cube can fill the entire prism.

3 0
2 years ago
What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4
Alecsey [184]

Answer:  f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: f(x)=\dfrac{3x^2}{x^2-4}

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}

i.e. y=\dfrac{3}{1}=3

Hence, f(x) will have horizontal asymptote at y=3.

3 0
3 years ago
We know that side NM is parallel to side XZ. If we consider side NY the transversal for these parallel lines, we create angle pa
Likurg_2 [28]
See the picture attached.

We know:
NM // XZ
NY = transversal line
∠YXZ ≡ ∠YNM

1) <span>We know that ∠XYZ is congruent to ∠NYM by the reflexive property.</span>

The reflexive property states that any shape is congruent to itself.
∠NYM is just a different way to call ∠XYZ using different vertexes, but the sides composing the two angles are the same.
Hence, ∠XYZ ≡ <span>∠NYM</span> by the reflexive property.

2) Δ<span>XYZ is similar to ΔNYM by the AA (angle-angle) similarity theorem

The AA similarity theorem states that if two triangles have a pair of corresponding angles congruent, then the two triangles are similar.
Consider </span>Δ<span>XYZ and ΔNYM:
</span>∠YXZ ≡ <span>∠YNM
</span>∠XYZ ≡ ∠NYM
Hence, ΔXYZ is similar to ΔNYM by the AA similarity theorem.


8 0
3 years ago
Read 2 more answers
PLEASE HELP QUICK 3t-2=-11
valentina_108 [34]
-3
step by step
add 2 to -11 and divide-9 by 3
5 0
3 years ago
Read 2 more answers
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