Answer:
k = ![\frac{980a}{b}](https://tex.z-dn.net/?f=%5Cfrac%7B980a%7D%7Bb%7D)
Step-by-step explanation:
Fisherman noticed a stretch in the spring = 'b' centimetres
Weight of the fish = a kilograms
If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,
F = kΔx
Where k = spring constant
Δx = stretch in the spring
F = weight applied
F = mg
Here 'm' = mass of the fish
g = gravitational constant
F = a(9.8)
= 9.8a
Δx = b centimetres = 0.01b meters
Therefore, 9.8a = k(0.01b)
k =
k = ![\frac{980a}{b}](https://tex.z-dn.net/?f=%5Cfrac%7B980a%7D%7Bb%7D)
Therefore, spring constant of the spring will be determined by the expression, k = ![\frac{980a}{b}](https://tex.z-dn.net/?f=%5Cfrac%7B980a%7D%7Bb%7D)
Answer:
(-3.07, 11.07)
Step-by-step explanation:
Given that a sports writer wished to see if a football filled with helium travels farther, on average, than a football filled with air. To test this, the writer used eighteen adult male volunteers. These volunteers were randomly divided into two groups of nine subjects each.
Group Group One Group Two
Mean 300.00 296.00
SD 8.00 6.00
SEM 2.67 2.00
N 9 9
The mean of Group One minus Group Two equals 4.00
standard error of difference = 3.333
df = 16
t = 1.2000
Margin of error = 3.3333* t critical = 3.3333*2.121
95% confidence interval of this difference: From -3.07 to 11.07
Answer:
C
Step-by-step explanation:
given:
m= -2 and (3, -1)
point-slope form: y-y1= m(x-x1)
y - (-1) = -2(x-3)
y + 1 = -2(x-3)