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irga5000 [103]
2 years ago
15

Help pls, will mark brainliest

Mathematics
1 answer:
BaLLatris [955]2 years ago
8 0

Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

The n'th term of a Arithmetic Sequence let's say it be {\sf T_n} is given by ;

  • {\boxed{\bf T_{n}=T_{1}+(n-1)d}}

Where , <u>d</u> is the common difference

Now , here we are given with ;

{\quad \qquad \sf \blacktriangleright \blacktriangleright \blacktriangleright T_{1}=8 \: and \: T_{5}=-4}

We have to find the 2nd , 3rd and 4th term respectively ,

Now , by using the above formula , 5th term can be written as ;

{: \implies \quad \sf T_{1}+(5-1)d=T_{5}}

Putting the values and transposing 1st term to RHS , we have ;

{: \implies \quad \sf 4d = -4-8}

{: \implies \quad \sf d=-\dfrac{12}{4}}

{: \implies \quad \sf d=-3}

Now , as we got the common difference , so we can find out the missing terms now ;

{: \implies \quad \sf T_{2}= T_{1}+(2-1)d}

{: \implies \quad \sf T_{2}= 8 +d}

{: \implies \quad \sf T_{2}= 8-3}

{: \implies \quad \bf \therefore \:  T_{2}= 5}

Now

{: \implies \quad \sf T_{3}= T_{1}+(3-1)d}

{: \implies \quad \sf T_{3}= 8 +2d}

{: \implies \quad \sf T_{3}= 8-6}

{: \implies \quad \bf \therefore \:  T_{3}= 2}

Also ,

{: \implies \quad \sf T_{4}= T_{1}+(4-1)d}

{: \implies \quad \sf T_{4}= 8 +3d}

{: \implies \quad \sf T_{4}= 8-9}

{: \implies \quad \bf \therefore \:  T_{4}= -1}

Now , The given table can be written as ;

{\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

brainly.com/question/26750175

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3 years ago
Convert from standard form to Slope intercept form: -2x + 5y = -15
yulyashka [42]
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The first thing we have to do here is move the term with the x variable over to the right side of the equation.

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