What is the discriminant in the quadratic equation x2 + 11x + 121 = x + 96?
A. 0
B. 100
C. 20
D. 200
2 answers:
X² + 11x + 121 = x + 96
x² + 11x - x + 121 - 96 = 0
x² + 10x + 25 = 0. Compare to ax² + bx + c = 0.
a = 1, b = 10, c = 25.
Discriminant, Δ = (b² - 4ac)
= (10² - 4*1*25)
= (100 - 100)
= 0.
Discriminant = 0
Option A.
Given:
x² + 11x + 121 = x + 96
First, we need to convert it into a quadratic equation.
x² + 11x - x + 121 - 96 = 0
x² + 10x + 25 = 0
a = 1 ; b = 10 ; c = 25
Quadratic formula:
x = (-b <u>+</u> (√b² - 4ac)) ÷ 2a
The discriminant is under the radical sign
discriminant ⇒ b² - 4ac ⇒ 10² - 4(1)(25) ⇒ 100 - 100 = 0
Correct answer is A. 0
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