Answer:
Step-by-step explanation:
k(k+1)(k+2) - 3k(k+1)
k and (k+1) are common to both terms.
k(k+1)(k+2) - 3k(k+1) = k(k+1)[(k+2) - 3] = k(k+1)(k-1)
whatttttt6 whattttt whattt
find all numbers, stick together o make an uqaion and solve . simplifi if needed
= 216
