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Drupady [299]
2 years ago
7

HELP PLEASE! Please explain Slovin's formula​

Mathematics
2 answers:
Arlecino [84]2 years ago
6 0

Answer:

who is slovin?????

Step-by-step explanation:

ycow [4]2 years ago
3 0

Answer:

I need more information, meaning his formula.

Step-by-step explanation:

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ABCD is a parallelogram.
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It is

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Which inequality is represented by this graph? A number line going from 1 to 9. A closed circle is at 4. Everything to the right
Fofino [41]

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x ≥ 4

Step-by-step explanation:

Since there is a closed circle at x = 4, this indicates that x can be equal to 4

The line to the right is shaded indicating values of x greater than 4

Thus x ≥ 4 ← is the inequality represented in the number line

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The complex number _______ lies in the shaded area of the graph. The complex number _______ does not lie in the shaded area.
Anastaziya [24]
Think of imaginary numbers on a complex plane as coordinates - take the real part, that's the x coordinate, the imaginary part that's the y coordinate.

Therefore, for the first blank, -1+3i lies in the shaded area, because its coordinates are (-1,3).
And following on from that for the second one, -4i does not lie in the shaded area, since its coordinates are (0,-4).

Tl;dr is taking a complex number a+bi and placing it on a complex plane, it will have coordinates (a,b)
5 0
3 years ago
Use theorem 7. 4. 2 to evaluate the given laplace transform. do not evaluate the convolution integral before transforming. (writ
irga5000 [103]

With convolution theorem the equation is proved.

According to the statement

we have given that the equation and we have to evaluate with the convolution theorem.

Then for this purpose, we know that the

A convolution integral is an integral that expresses the amount of overlap of one function as it is shifted over another function.

And the given equation is solved with this given integral.

So, According to this theorem the equation becomes the

\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{ \mathscr{L} (e^{-\tau} \cos \tau ) }{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{\frac{s+1}{(s+1)^2+1}}{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{1}{s}\left (\frac{s+1}{(s+1)^2+1} \right).

Then after solving, it become and with theorem it says that the

\mathscr{L} \left( \int_{0}^{t} f(\tau) d\tau \right) = \frac{\mathscr{L} ( f(\tau))}{s} .

Hence by this way the given equation with convolution theorem is proved.

So, With convolution theorem the equation is proved.

Learn more about convolution theorem here

brainly.com/question/15409558

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