Here is a picture with the answer.
Answer:
x=
3
/2
Step-by-step explanation:
12(5x−4.5)=36
(12)(5x)+(12)(−4.5)=36(Distribute)
60x+−54=36
60x−54=36
Step 2: Add 54 to both sides.
60x−54+54=36+54
60x=90
Step 3: Divide both sides by 60.
60x
60
=
90
/60
x=
3
/2
Convert the timing into hours only:
11:15 = 11.25h
9:45 = 9.75h
11:45 = 11.75h
7:45 = 7.75h
10:45 = 10.75h
To find the average, we need to find the middle of these timing:
11.25 + 9.75 + 11.75 + 7.75 + 10.75 = 51.25
51.25 ÷ 5 = 10.25h = 10:15 am
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Answer: The average time it docks is 10:15 am.
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Answer:
The answer is B) 0.57.
Step-by-step explanation:
In this problem we have to apply queueing theory.
It is a single server queueing problem.
The arrival rate is
and the service rate is
.
The proportion of time that the server is busy is now as the "server utilization"and can be calculated as:

where c is the number of server (in this case, one server).