$\bf 2log(x-3)+1=5\iff 2log_{10}(x-3)+1=5\\\\\\ 2log_{10}(x-3)=4
\\\\\\
log_{10}(x-3)=\cfrac{4}{2}\implies log_{10}(x-3)=2\\\\
-----------------------------\\\\
{{ a}}^{log_{{ a}}x}=x\impliedby \textit{using this cancellation rule}\\\\
-----------------------------\\\\
10^{\cfrac{}{}log_{10}(x-3)}=10^2\implies x-3=10^2\implies x=100+3$

5 0

3 years ago

Help me i dont know what i am doing at all

nika2105 [10]

You are doing the distributive property.
68.5j+76.54

7 0

3 years ago

If P = (-2,7), Find:<br> Rx-1(P)<br> ([?], [])

dexar [7]

Answer is (4,7)

Step-by-step explanation:

6 0

2 years ago