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3 years ago

Y = 3x

Mathematics

2 answers:

Y_Kistochka [10]3 years ago

6 0

Answer:

<h3>A. One solution</h3>

Step-by-step explanation:

as well as the formula of one solution is

a1/a2 ≠ b1/b2

so 1/1 ≠ 3/1 × 2/1

1/1 ≠ 6/1

so the solution of the equation is A. one solution

In elimination method since the coefficient is y= 1 it become same by this method.

Dima020 [189]3 years ago

4 0

Answer:

Step-by-step explanation:

y = 3x + 0

y = 1/2x + 0

y = 3x + 0

-3x -3x

y - 3x = 0

y = 1/2x + 0

2(y = 1/2x + 0)

2y = x + 0

-x -x

2y - x = 0

y - 3x = 0

2y - x = 0

1(y - 3x = 0) = y = - 3x = 0

-3(2y - x = 0) = -6y + 3x = 0

y = - 3x = 0

-6y + 3x = 0

-5y = 0

/-5 /-5

y = 0

y = 3x + 0

0 = 3x + 0

-3x -3x

-3x + 0 = 0

- 0 -0

-3x = 0

/-3 /-3

x = 0

(x,y) -> (0, 0)

Hope this helps!

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3 years ago

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mario62 [17]

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Step-by-step explanation:

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4 years ago

Read 2 more answers

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jek_recluse [69]

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$f(z) = {z}^{2} - 3 \times z + 2 \\ \\ {z}^{2} - 3z + 2 \\ \\ {z}^{2} - 2z - z + 2 \\ \\ z(z - 2) - 1(z - 2) \\ \\ (z - 1)( z -2 ) \\ \\ (z - 1) = 0 \: \: , \: \: (z - 2) = 0\\ \\ z = 1 \:, \: 2$

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$f( \sqrt{2} + 1) = {x}^{2} - 3x + 2 \\ \\ {( \sqrt{2} + 1) }^{2} - 3( \sqrt{2} + 1) + 2 \\ \\ 2 + 1 + 2\sqrt{2} - 3 \sqrt{2} - 3 + 2 \\ \\ 3 - 1 \sqrt{2} - 1 \\ \\ 2 - \sqrt{2} \\ \\ 2 - 1.4 (optional \: \: \: steps)\\ \\ 0.6 \: \:$

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2 years ago

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gogolik [260]

Answer:

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Step-by-step explanation:

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