Please answer class 7 maths i will make brainleast
1 answer:
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The complete question in the attached figure
we know that
tan ∠AOB=opposite side angle ∠AOB/adjacent side angle ∠AOB
opposite side angle ∠AOB=1
adjacent side angle ∠AOB=√3
angle ∠AOB=pi/a radians
so
tan (pi/a)=1/√3---------> tan (pi/a)=√3/3
we know that
tan 30°=√3/3
30° is equal to pi/6 radians
and
angle (pi/a) belong to the I quadrant
so
(pi/a)=pi/6
a=6
the answer is
a=6
we know that
tan ∠AOB=opposite side angle ∠AOB/adjacent side angle ∠AOB
opposite side angle ∠AOB=1
adjacent side angle ∠AOB=√3
angle ∠AOB=pi/a radians
so
tan (pi/a)=1/√3---------> tan (pi/a)=√3/3
we know that
tan 30°=√3/3
30° is equal to pi/6 radians
and
angle (pi/a) belong to the I quadrant
so
(pi/a)=pi/6
a=6
the answer is
a=6