If you are framing a photo that is 4in by 7 in, and you want the frame to be the same width all around, and the total area of th
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Hey there :)
We know the distance formula is:
D =
1) Coordinates are: ( -10, -5 ) , ( 8 , 5 )
↓ ↓ ↓ ↓
x₁ y₁ x₂ y₂
We plug in the values
D =
≈20.59 ≈ 20.6 (nearest tenth)
We do the same for the rest
2) Coordinates are ( 10 , 0 ) , ( -2 , 1 )
D =
≈ 12.04 ≈ 12.0 (nearest tenth)
3) Coordinates are ( 4 , 8 ) , ( 7 , -8 )
D =
≈ 16.27 ≈ 16.3 (nearest tenth)
4) Coordinates are ( -10, -4 ) , ( 8 , 8 )
D =
≈ 21.6 (nearest tenth)
5) Coordinates are ( 6 , -3 ) , ( -8 , 9 )
D =
≈ 18.4 (nearest tenth)
You can find the matching below :)
We know the distance formula is:
D =
1) Coordinates are: ( -10, -5 ) , ( 8 , 5 )
↓ ↓ ↓ ↓
x₁ y₁ x₂ y₂
We plug in the values
D =
≈20.59 ≈ 20.6 (nearest tenth)
We do the same for the rest
2) Coordinates are ( 10 , 0 ) , ( -2 , 1 )
D =
≈ 12.04 ≈ 12.0 (nearest tenth)
3) Coordinates are ( 4 , 8 ) , ( 7 , -8 )
D =
≈ 16.27 ≈ 16.3 (nearest tenth)
4) Coordinates are ( -10, -4 ) , ( 8 , 8 )
D =
≈ 21.6 (nearest tenth)
5) Coordinates are ( 6 , -3 ) , ( -8 , 9 )
D =
≈ 18.4 (nearest tenth)
You can find the matching below :)
