Answer:
2.069x10^3
Step-by-step explanation:
Move the decimal places.
Answer:
- Let p be the population at t be the number of years since 2011. Then,

- The projected population of the high school in 2015=1800
- In <u>2019</u> the population be 1600 students
Step-by-step explanation:
Given: The population at Bishop High School students in 2011 =2000
Also, Every year the population decreases by 50 students which implies the rate of decrease in population is constant.
So, the function is a linear function.
Let p be the population at t be the number of years since 2011.
Then, 
So at t=0, p=2000
In year 2015, t=4, substitute t=4 in the above equation ,we get

Hence, the projected population of the high school in 2015=1800
Now, put p=1600 in the function , we get

Now, 2011+8=2019
Hence, in <u>2019</u> the population be 1600 students
27 divided by 55= 0.490909 repeating
Step by Step Explanation:
picture below
Answer:
Jenny is wrong the correct answer is x²+ 4 - 4 x.
Step-by-step explanation:
Given that
(x-2)³∕x-2
(x-2)³∕(x-2) =(x-2) (x-2)²∕(x-2)
(x-2)³∕(x-2) = (x-2)²
As we know that
(a-b)² = a²+b² - 2 ab
So
(x-2)² = x²+ 2² - 2 ˣ 2 ˣ x = x²+ 4 - 4 x
(x-2)² = x²+ 4 - 4 x
It means that
(x-2)³∕(x-2) = (x-2)² = x²+ 4 - 4 x
So Jenny is wrong the correct answer is x²+ 4 - 4 x.
Answer:
Step-by-step explanation:
A. The first inequality is graphed as a shaded area below the solid line with x-and y-intercepts of 7.5 and 5, respectively. The second inequality is graphed as a shaded area above the solid line with x- and y-intercepts of 3.
The solution set is the set of integer-valued grid points one or between the lines.
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B. The point (5, 1) is included in the solution area. Mathematically, it can be shown to satisfy the two inequalities:
2(5) +3(1) ≤ 15 ⇒ 13 ≤ 15 True
(5) +(1) ≥ 3 ⇒ 6 ≥ 3 True
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C. The point (5, 1) is in the solution set. It means Michael can purchase 5 sandwiches and 1 hot lunch within his budget constraints. That will provide 6 meals, which is more than the minimum of 3 that he wants to provide.