Pls help me solve this.

Who has the best conclusion?

Nataliya [291]

Answer:

B. Shania's conclusion is the only accurate one.

Step-by-step explanation:

7 0

3 years ago

If a = 4, Evaluate 35 - 3a

Aloiza [94]

Answer:

23

Step-by-step explanation:

3 times 4 equals 12

then do

35 minus 12

6 0

3 years ago

Read 2 more answers

An angry student murdered Tommy the Turtle near the northern fence of the park. Using yellow tape,Ranger Dave is marking off a r

pishuonlain [190]

Answer:

60ft

Step-by-step explanation:

Let's x, y be the width and length of the surrounding rectangle. Since the area is 450 sq feet, this means xy = 450 or y = 450/x

The perimeter of this rectangle is (since there are 3 sides only)

f(x,y) = 2x + y

This is something we need to minimize. We can start by substituting y = 450/x

f(x) = 2x + 450/x

Let's take the first derivative of this function and set it to 0

$f'(x) = 2 - \frac{450}{x^2} = 0$

$2 = \frac{450}{x^2}$

$x^2 = 450 / 2 = 225$

$x = \sqrt{225} = 15ft$

y = 450 / 15 = 30ft

so the minimum perimeter that needs taping over is

f(x,y) = 2x + y = 2*15 + 30 = 60ft

5 0

3 years ago

The number of loaves of bread purchased and the total cost of the bread in dollars can be modeled by the equation c = 3. 5b. Whi

Dmitrij [34]

The dependent variable is the variable that depends on the value of other variable and keeps on changes with change in the value of one variable. The values given in the table 3 matches the equation and includes the viable solutions.

<h3>Given information-</h3>

The number of loaves of bread purchased and the total cost of the bread in dollars can be modeled by the equation,

$c=3.5b$

The quantity of the bread depends on the quantity of the loaves.

<h3>Dependent variable</h3>

The dependent variable is the variable that depends on the value of other variable and keeps on changes with change in the value of one variable.

Lets check which table satisfy the above equation.

Table 1-

In the table the first values of the bread and the loves is -2 and -7. The quantity of a bread and loves can not be negative. Thus the table 1 does not provides the viable solution.

Table 2-

In the table 2 the value of the third row is 1.5 loaves and 5.25 breads. Check this by the given equation. When the value of loaves is 1.5 then the value of the bread is,

$c=3.5\times1.5$