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3 years ago

Greatest common factor of 48,120

2 answers:

5 0

$Hello. 

Let's figure this out.

I'll list all the factors to help us answer your question. 

48: 1
2
3
4
6
8
12
16
24
48

120: 1
2
3
4
5
6
8
10
12
15
20
24
30
40
60
120 

We can see that the GREATEST common factor (GCF) between

49 and 120 is: 24

You're welcome.$

Deffense [45]3 years ago

3 0

The GCF (Greatest Common Factor) of 48 & 120 would be 24.

I got the answer by seeing what number can can go into both 48 and 120 so 24 can go into 48 by 2 since 24 x 2 = 48 = true and 24 can go into 120 by 5 since 24 x 5 = 120.

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3 years ago

Need help doing this, show steps if you could

Anna71 [15]

Answer:

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3 years ago

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Step-by-step explanation:

5 0

2 years ago

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The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

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3 years ago

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3 years ago

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