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4 years ago

Greatest common factor of 48,120

2 answers:

5 0

$Hello. 

Let's figure this out.

I'll list all the factors to help us answer your question. 

48: 1
2
3
4
6
8
12
16
24
48

120: 1
2
3
4
5
6
8
10
12
15
20
24
30
40
60
120 

We can see that the GREATEST common factor (GCF) between

49 and 120 is: 24

You're welcome.$

Deffense [45]4 years ago

3 0

The GCF (Greatest Common Factor) of 48 & 120 would be 24.

I got the answer by seeing what number can can go into both 48 and 120 so 24 can go into 48 by 2 since 24 x 2 = 48 = true and 24 can go into 120 by 5 since 24 x 5 = 120.

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In the rectangle below, AE = 3x + 6, CE =6x-9, and mZEDA= 55°. Find BE and m ZEAB.

tekilochka [14]

Answer:

BE = 21

m∠EAB = 45°

Step-by-step explanation:

The given dimensions in the rectangle are;

The length of AE = 3·x + 6

The length of CE = 6·x - 9

m∠EDA = 55°

From the properties of a rectangle, we have;

The diagonals of a rectangle bisect each other,

The lengths of the diagonals are equal

Therefore;

AC = BD

Diagonal BD bisects diagonal AC, therefore, AE = CE

Plugging in the values of AC and AE, we have;

3·x + 6 = 6·x - 9

∴ 6·x - 3·x = 6 + 9 = 15

3·x = 15

∴ x = 15/3 = 5

Therefore, we have;

AE = CE = 3·x + 6 = 3×5 + 6 = 21

AC = AE + CE = 21 + 21 = 42 = BD

BD = BE + DE and for rectangle ABCD, BE = DE

∴ BD = BE + BE = 2·BE = 42

∴ BE = 42/2 = 21

BE = 21

m∠EDA = m∠EAD = 55° by base angle of isosceles triangle ΔAED

m∠DAB = 90° = m∠EAD + m∠EAB

∴ m∠EAB = 90° - m∠EAD = 90° - 55° = 45°

m∠EAB = 45°.

7 0

3 years ago

The equation A = p + prt is used to find the accumulated amount, A, of an investment with principal, P, a certain interest rate,

Whitepunk [10]

Answer:

r equals start fraction cap a minus p over p t end fraction

Step-by-step explanation:

Subtract the term non containing r, then divide by the coefficient of r.

$A=p+prt\\\\A-p=prt\\\\\dfrac{A-p}{pt}=r$

4 0

3 years ago

Do number 4 please DONT get it wrong or i block report, i really need help please :)

andriy [413]

Area of the figure = 30.28 m²

Solution:

The given image is splitted into two shapes.

One is rectangle and the other is semi-circle.

Length of the rectangle = 6 m

Width of the rectangle = 4 m

Area of the rectangle = length × width

= 6 m × 4 m

= 24 m²

Area of the rectangle = 24 m²

Diameter of the semi-circle = 4 m

Radius of the semi-circle = 4 m ÷ 2 = 2 m

Area of the semi-circle = $\frac{1}{2} \ \pi r^2$

$$=\frac{1}{2} \times 3 .14 \times 2^2$

$=6.28$

Area of the semi-circle = 6.28 m²

Area of the figure = Area of the rectangle + Area of the semi-circle

= 24 m² + 6.28 m²

= 30.28 m²

Area of the figure = 30.28 m²

3 0

3 years ago

What is the equation of the line through the origin and (3, 4)?

alisha [4.7K]

Answer:

y = 4/3x

Step-by-step explanation:

Hope that helps you

3 0

3 years ago

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erma4kov [3.2K]

Answer:

It can't be simplified.

6 0

3 years ago