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nalin [4]
3 years ago
14

What would be the length and width of a 50" TV that has an aspect ratio of 4:3?

Mathematics
1 answer:
Reika [66]3 years ago
4 0

Check the picture below.

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Helppp I’m not good with this stuff lol
Natasha2012 [34]

Answer:

that is you my question is wrong for me

6 0
3 years ago
Which value is a solution of the equation x2 (squared) = 49?
Talja [164]

Answer:

24.5

Step-by-step explanation:

If you multiply 2 and 24.5 together you would get 49

8 0
3 years ago
Read 2 more answers
Find the equation of the quadratic function whose graph is a parabola containing the points (0,2), (3,26), and (-1,6).
Arlecino [84]

Answer: y = 3x^2 -x + 2

Step-by-step explanation:

8 0
4 years ago
f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2
iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4,\infty)

g(x)=2x^2+8x+6=2(x^2+4x+3)

g(x)=0

2(x^2+4x+3)=0

x^2+4x+3=0

x^2+3x+x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

x+1=0\implies x=-1

x+3=0\implies x=-3

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2

g(x)=2(x^2+4x)+6

g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6

g(x)=2(x+2)^2-2

By comparing with the equation of parabola

y=a(x-h)^2+k

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2,\infty)

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0
3 years ago
Mrs. Miller has a rectangular garden with a length of 20 feet long with an area of (20x-200) square feet. Write an expression th
krek1111 [17]

Perimeter = (20 + 2x) mm.

Step-by-step explanation:

The octopus pupil has length 20 mm and the expression for its area is given by (20x - 200) square mm.

If the width of the octopus pupil is w, then 20w = 20x - 200

⇒ w = (x - 10) mm.

Therefore, the expression for its perimeter is 2(Length + Width) = 2 ( 20 + x - 10) = 2( 10 + x) = (20 + 2x) mm. (Answer)

6 0
3 years ago
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