Answer:
give me 2 minutes and I will
Answer:
let p(x)=180
LCM=720
HCF=36
WE HAVE TO FIND q(x)=?
as we know that
p(x)×q(x)=LCM×HCF
NOW WE HAVE TO FIND q(x)
q(x)=LCM×HCF/p(x)
q(x)=720×36/180
q(x)=25920/180
q(x)=144
i hope this will help you
Please consider the complete question.
A parking lot in the shape of a trapezoid has an area of 12,052.1 square meters. The length of one base is 82.4 meters and the length of the base is 108.6 meters. What is the width of the parking lot
We will use area of trapezoid to formula to solve our given problem.
, where
a and b represents parallel sides of trapezoid,
h = height of trapezoid.
Width of the trapezoid will be equal to height.
Upon substituting our given values in above formula, we will get:





Therefore, the width of the parking lot is 126.2 meters.
Answer:
1,120 yd²
Step-by-step explanation:
Surface area of triangular prism = 2(BA) + P*H
✔️Triangular base area (BA) = ½bh
b = 15 yd
h = 8 yd
Base area (BA) = ½*8*15 = 60 yd²
✔️Perimeter of the base (P) = 17 + 15 + 8 = 40 yd
✔️Height or lenghtbor prism (P) = 25 yd
✔️Surface area = 2(60) + 40*25 = 120 + 1,000 = 1,120 yd²
You have to divide 3 by 1/3 and you get 9. So he has 9 balls.
I hope this helps