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2 years ago

Find the number of degrees in the third angle of the triangle.

Mathematics

2 answers:

sleet_krkn [62]2 years ago

5 0

Answer:

x = 42°

explanation:

The sum of total angles in a triangle is 180°

solve:

95° + 43° + x° = 180°

138° + x° = 180°

x = 180° - 138°

x = 42°

Nadya [2.5K]2 years ago

4 0

Solution:

95 + 43 + x = 180

<u>Simplify the equation to find x.</u>

95 + 43 + x = 180
=> 138 + x = 180
=> x = 180 - 138
=> x = 42°

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How many different rectangular prisms can he build if he uses all the cubes

pishuonlain [190]

It depends on how you count them. If you describe them by their dimensions, lowest one first, you can have
1 x 1 x 18
1 x 2 x 9
1 x 3 x 6
2 x 3 x 3

Of course, these dimensions can be put in any order.

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3 years ago

Given the function defined in the table below, find the average rate of change, in simplest form, of the function over the inter

slava [35]

Using it's concept, the average rate of change of the function over the interval 10 < x < 22 is given by:

$r = \frac{f(22) - f(10)}{12}$

<h3>What is the average rate of change of a function over an interval?</h3>

It is given by the change in the <u>output divided by the change in input</u>.

Over the interval 10 < x < 22, the outputs are f(10) and f(22), hence the rate of change is given by:

$r = \frac{f(22) - f(10)}{12}$

More can be learned about the average rate of change of a function at brainly.com/question/24313700

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2 years ago

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AVprozaik [17]

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1 year ago

Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)

adelina 88 [10]

Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

4 0

3 years ago

How do I solve these for example 3

Natasha2012 [34]

As the three longitudinal lines are parallel:

angle 4 = 5 = 6 = 82 degree (corresponding angles) = 9 = 8 = 7 = 82 degrees (vertical angles)

and

angle 11 = 180-82= 98 degrees (linear pair)

so:

angle 10 = 11 = 12 = 98 degrees (corresponding angles) = 3 = 2 = 1 = 98 degrees (vertical angles)
.

hope you got it

8 0

3 years ago