The slope of a line that is perpendicular to the line y = 8x + 5 will be -1/8.
<h3>What is the slope of perpendicular lines?</h3>
Suppose that first straight line has slope 's'
Let another straight line be perpendicular to this first line.
Let its slope be 'a'
Then due to them being perpendicular, they have their slopes' multiplication as -1
or
s x a = -1
s = -1/ a
Slope of line y = 8x + 5
s = 8
The slope of a line that is perpendicular to the line y = 8x + 5
8 x a = -1
a = -1/8
Thus, the slope is -1/8.
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Answer:
20 units
Step-by-step explanation:
s = 8
Perimeter = s + s + 
= 8 + 8 + 4
= 20 units
Answer:
21$
Step-by-step explanation:
42÷6=7
7×3=21
Answer:
The first equation, sorry can’t explain.
First, let's find the slope of the line from the points given.
m = (4 - - 2) / (3 - 1)
m = 6 / 2
m = 3
Secondly, we know that a line perpendicular to the original must have a slope that is the opposite reciprocal of the original. For the given points, the opposite reciprocal slope would be -1/3.
Now, we can put all of the equations below into slope intercept form and find the ones that have a slope of -1/3.
Equation 1: Correct
y = -1/3x - 5
Equation 2: Incorrect
y = 3x - 3
Equation 3: Incorrect
y - 2 = 3(x + 1)
y - 2 = 3x + 1
y = 3x + 2
Equation 4: Correct
x + 3y = 9
3y = -x + 9
y = -1/3x + 3
Equation 5: Incorrect
3x + y = -5
y = -3x - 5
Hope this helps!! :)
