Answer:
C. ± 2.326 years.
Step-by-step explanation:
We have the standard deviation for the sample. So we use the t-distribution to solve this question.
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so ![z = 2.326/tex]Now, find the width of the interval[tex]W = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=z%20%3D%202.326%2Ftex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3ENow%3C%2Fstrong%3E%2C%20find%20the%20width%20of%20the%20interval%3C%2Fp%3E%3Cp%3E%5Btex%5DW%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which 
is the standard deviation of the population and n is the size of the sample.
In this question:
So
The correct answer is:
C. ± 2.326 years.
Answer:
c = F-32; 68-32 = 36°C.
Step-by-step explanation:
the real conversation equation is f = 9/5 C + 32. but for the sake of this problem we are ignoring the coefficient.
so it's 36°C
A solution something something and that’s the answer
Answer:
20 portions
Step-by-step explanation:
2 kg = 2000 g
2000 / 100 = 20
Hope this helped! :)
Simplify the radical by breaking the radicand up into a product of known factors in other words take the cube root of 27 then for the exponent 9 you divide by 3 get
3x^3
