Answer:
Therefore the volume of the box is 13824 in³
Step-by-step explanation:
Given:
A spherical ball with is packaged in a box that is in the shape of a cube.
Volume of ball = 2304π in³.
Let 'r' be the radius of sphere
To Find:
Volume of Cube = ?
Solution:
Volume of sphere is given by
Substituting the values we get
Now we know that diameter is given by
it is given that,
The edge length of the box is equal to the diameter of the ball.
Therefore the length of cube = 24 in
Now the volume of the cube is given by
substituting the values we get
Therefore the volume of the box is 13824 in³
Answer:
the real answer is 1107.5 ft
3
Step-by-step explanation:
Volume of Cone:
V=\frac{1}{3}\pi r^2h
V=
3
1
πr
2
h
\text{Find radius:}
Find radius:
r=\frac{\text{diameter}}{2}=\frac{17.2}{2}=8.6
r=
2
diameter
=
2
17.2
=8.6
h=14.3\hspace{40px}r=8.6
h=14.3r=8.6
Needed information
V=
V=
\,\,\frac{1}{3}\pi r^2h
3
1
πr
2
h
V=
V=
\,\,\frac{1}{3}\pi (8.6)^2(14.3)
3
1
π(8.6)
2
(14.3)
Plug in
V=
V=
\,\,1107.54545168
1107.54545168
Evaluate in calculator
V\approx
V≈
\,\,1107.5\text{ ft}^3
1107.5 ft
3
3/5 = 0.6
0.15 = 3/20
7/8 = 0.875
0.725 = 29/40
Answer:
- <em>B) 41 − 45; 46 − 50; 51 − 55; 56 − 60 </em>
Explanation:
When you build a <em>histogram </em>the intervals must be of the same size. About 4 to 8 intervals is good but it also depends on the number of data and the range of those data.
Option D has only two intervals. That is too few. Thus, this is discarded. Three intervals also seems few. Thus, option C, is not good.
The option A shows intervals of different size:
- 46 - 41 = 4
- 49 - 46 = 3
- 52 - 49 = 3
- 56 - 53 = 3
Thus, this is not good either.
The optio B seems good:
Interval Frequency
- 45 - 41 = 4 3
- 50 - 46 = 4 4
- 55 - 51 = 4 4
- 60 - 56 = 4 1
Hence, the correct answer is B) 41 − 45; 46 − 50; 51 − 55; 56 − 60
