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3 years ago

Please help i am very confused

Mathematics

1 answer:

Step2247 [10]3 years ago

4 0

Answer:

$\sqrt{80}$

80 is the number in the square root

Step-by-step explanation:

$d = \sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} } \\d = \sqrt{(4-(-4) )^{2} +(5- 1 )^{2} }\\d = \sqrt{(4+4 )^{2} +4^{2}\\d = \sqrt{8^{2} +4^{2} }\\d=\sqrt{64 +16}\\d=\sqrt{80}$

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What is the solution to the system of equations? (-2,4), (3,4), (4,-2), (4,3)

sergey [27]

Answer: 43/10

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Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Person 1 writes internal operating procedures 3 times faster than Person 2. Most of the procedures took 30 minutes each to creat

ad-work [718]

Person 1 takes 3 hour 10 minutes to complete 9 procedures

Solution:

From given question,

Person 2 takes 30 minutes per procedure

Person 1 writes internal operating procedures 3 times faster than Person 2

So we get, Person 1 takes 3 times faster than Person 2

Person 1 takes 10 minutes per procedure

But two of the procedures for Person 1 took an hour each

So person 1 takes 60 minutes each for two of procedures ( since 1 hour = 60 minutes )

Calculate how long it took Person 1 to complete 9 procedures:

So for first 7 procedures person 1 would take 10 minutes per procedure and for last two procedures person 1 would take 60 minutes per procedure

$time $=7$ procedures $\times \frac{10 \text { minutes }}{1 \text { procedure }}+2$ procedure $\times \frac{60 \text { minutes }}{1 \text { procedure }}$$

$time=70 minutes +120minutes\\\\time=190minutes$

We know that,

1 hour = 60 minutes

Therefore,

190 minutes = 60 minutes + 60 minutes + 60 minutes + 10 minutes

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Therefore Person 1 takes 3 hour 10 minutes to complete 9 procedures

7 0

3 years ago

Five sevenths times seven thirds

lord [1]

5/7 x 7/3

Multiply the numerators together and the denominators:

(5 x 7) / (7 x 3)

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3 years ago

Y=4x^2-36 solve the following quadratic function by utilizing the square root method x=?

Luda [366]

Answer:

This ans is easily solved by using algebraic identities a²- b² = (a+b) (a-b)

Step-by-step explanation:

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2 years ago

7th term of (c-d)^10

lutik1710 [3]

$\bf (c-d)^{10}\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&+1&(c)^{10}(-d)^0\\
2&+10&(c)^9(-d)^1\\
3&+45&(c)^8(-d)^2\\
4&+120&(c)^7(-d)^3\\
5&+210&(c)^6(-d)^4\\
6&+252&(c)^5(-d)^5\\
7&+210&(c)^4(-d)^6
\end{array}$

as you notice, the first term from the binomial, starts off with a highest exponent of 10, and then gradually goes down by 1 on every element.

the second term of the binomial, starts off with an exponent of 0, and goes up by 1 on every element.

now, to get the coefficient
the first coefficient is 1 and the second is the same as the binomial's exponent... those two are simple.... now, to get any subsequent one, we simply "get the product of the current coefficient and the exponent of the first term, and divide it by the exponent of the second term on the next element".

for example... how do we get 10 for the second element, basically 1 * 10/1

that one is simple

now how do we get say, 45 for the 3rd element?
10 * 9 / 2

how do we get 252 for the 6th element?
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and so on, and from there, you can expand each element.

4 0

4 years ago