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schepotkina [342]
2 years ago
7

You roll a 6-sided die. What is P(odd)? Write your answer as a fraction or whole number.

Mathematics
1 answer:
Troyanec [42]2 years ago
7 0

Answer:

the chances of you gettin a odd number is 3/6 since you have 1 3 and 5

Step-by-step explanation:

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One-fifth the sum of one-half and one-third. WRITE IN A EXPRESSION FORM
vladimir2022 [97]

Answer:

1/6

Step-by-step explanation:

1/2 + 1/3 = 5/6

1/5 of 5/6 = 5/30

5/30 can be simplified as 1/6.

8 0
2 years ago
Solve for (4x+6)+(-x+2) please i need help
postnew [5]

Answer:

3x - 8

Step-by-step explanation:

Step 1:

( 4x + 6 ) + ( - x + 2 )

Step 2:

4x - 6 + - x - 2

Step 3:

3x - 6 - 2

Answer:

3x - 8

Hope This Helps :)

8 0
3 years ago
Read 2 more answers
I am lost on what to do
Neko [114]
\bf sin({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[cos({{ \alpha}}-{{ \beta}})\quad -\quad cos({{ \alpha}}+{{ \beta}})]
\\\\\\
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\\\\
-----------------------------\\\\
\lim\limits_{x\to 0}\ \cfrac{sin(11x)}{cot(5x)}\\\\
-----------------------------\\\\
\cfrac{sin(11x)}{\frac{cos(5x)}{sin(5x)}}\implies \cfrac{sin(11x)}{1}\cdot \cfrac{sin(5x)}{cos(5x)}\implies \cfrac{sin(11x)sin(5x)}{cos(5x)}

\bf \cfrac{\frac{cos(11x-5x)-cos(11x+5x)}{2}}{cos(5x)}\implies \cfrac{\frac{cos(6x)-cos(16x)}{2}}{cos(5x)}
\\\\\\
\cfrac{cos(6x)-cos(16x)}{2}\cdot \cfrac{1}{cos(5x)}\implies \cfrac{cos(6x)-cos(16x)}{2cos(5x)}
\\\\\\
\lim\limits_{x\to 0}\ \cfrac{cos(6x)-cos(16x)}{2cos(5x)}\implies \cfrac{1-1}{2\cdot 1}\implies \cfrac{0}{2}\implies 0
4 0
3 years ago
4 times a number is increased by 15, the answer is the same as when 70 is decreased by the number
pentagon [3]

4n+15=70+n


I'm pretty sure this is the answer

Have a good day!

3 0
3 years ago
Read 2 more answers
A line passes through the points (–5, 2) and (10, –1). Which is the equation of the line?
beks73 [17]

Slope = (2 + 1) / (-5 - 10) = -3/15 = - 1/5

Equation

y - 2 = -1/5 (x + 5)

y - 2 = -1/5 x - 1

y = -1/5 x + 1

Answer

y = -1/5 x + 1

6 0
3 years ago
Read 2 more answers
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