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3 years ago

Pls help I've gotten every question wrong

Mathematics

1 answer:

Jlenok [28]3 years ago

3 0

4 pack: 13/4=3.25
5 pack: 16/5=3.2
8 pack: 28/8= 3.5

the 5 pack is the cheapest per bulb so it has the best value

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Which statement is true about the line represented on the equation y + 7 = -3 (x - 2/9) ?

Zarrin [17]

<u>ANSWER</u>

The point $(\frac{2}{9},-7)$ lies on the straight line $y+7=-3(x-\frac{2}{9})$

<u>EXPLANATION</u>

The given line is $y+7=-3(x-\frac{2}{9})$ . It can be observed that the given straight line is in the point-slope form.

We can rewrite the equation in the point-slope form to obtain,

$y--7=-3(x-\frac{2}{9})$ .

When we compare this to the general point-slope form, which given by the formula;

$y-y_1=m(x-x_1)$ ,

We can observe that,

$x_1=\frac{2}{9}$ and $y_1=-7$ .

Hence the point, $(x_1,y_1)=(\frac{2}{9},-7)$ lies on $y+7=-3(x-\frac{2}{9})$

6 0

4 years ago

Find the side lengths asked below:

charle [14.2K]

Answer:

WZ=

UZ=

Step-by-step explanation:

First, you have to find the x.

3x-6+x+6

Combine like terms

(3x+x) (-6+6)

4x+0

x=4.

WZ=3(4)-6

12-6

UZ= (4)+6

5 0

3 years ago

Prove each of these identities.

Stella [2.4K]

Answer:

Identity (a) can be re-written as

$sec x\ cosec x - cot x = tan x$

which we already proven in another question, while for idenity (b)

$(A)\frac 1 {sin x} -sin x = cos x \frac{cos x}{sin x}\\\\(B)\frac {1-sin^2x}{sin x} = \frac {cos^2x} {sin x} \\\\(C) \frac {cos^2x}{sin x} =\frac {cos^2x} {sin x}$

step A is simply expressing each function in terms of sine and cosine.

step B is adding the terms on the LHS while multiplying the one on RHS.

step C is replacing the term on the numerator with the equivalent from the pithagorean identity $cos^2x + sin^2x = 1$

8 0

2 years ago

Log 15 (2x − 2) = log 15 (x+9)

notka56 [123]

Answer:

$x=11$

Step-by-step explanation:

Given the equation

$\log_{15}(2x-2)=\log_{15}(x+9)$

Note that

$2x-2>0\\ \\2x>2\\ \\x>1$

and

$x+9>0\\ \\x>-9$

Combined, $x>1$

Solve the equation:

$2x-2= x+9\\ \\2x-x=9+2\\ \\x=11$

Since $11>1,$ this is the solution to the equation.

5 0

4 years ago

Two thousandths in decimal

Sholpan [36]

decimal tenths hundredths thousandths

.002

8 0

4 years ago

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