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Viefleur [7K]
3 years ago
14

the mean height of the team is 200.3 .a new player joins and raises the mean average height to 201cm. work out the height of the

new player.
Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0

Question

The table shows the heights in a basketball team.

Height: 198, 199, 200, 201, 202

a.) Work out the mean height of the team. Round you answer to 1d.p.

That, I have worked out is 200.3

b.) A new player joins the team and raises the mean average height to 201cm. Work out the height of the new player.

Answer:

206 cm

Step-by-step explanation:

The sum of the fiven numbers, 198+199+200+201+202=1000

For a mean of 201, the product should be 201*6=1206

The difference of the two is equivalent to the height of the other person hence 1206-1000=206 cm

Therefore, the height is 206 cm

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Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu
Softa [21]

<u>Answer-</u>

<em>The polynomial function is,</em>

y=x^4-10x^3+38x^2-64x+40

<u>Solution-</u>

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))   ( ∵ (3-i) is the conjugate of (3+i) )

\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)

\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)

\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)

\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)

\Rightarrow y=(x^2-4x+4)(x^2-6x+10)

\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10

\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40

\Rightarrow y=x^4-10x^3+38x^2-64x+40

Therefore, this is the required polynomial function.


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3 years ago
I NEED HELP PLEASE THANK YOU ​
Sauron [17]

Answer:

d

Step-by-step explanation:

if you tried to do the d you would end up with this

/_)

7 0
2 years ago
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