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valentina_108 [34]
2 years ago
8

Help me please!!!!!!​

Mathematics
2 answers:
Masteriza [31]2 years ago
7 0

\bold{\huge{\underline{ Solution }}}

<h3><u>Given :-</u></h3>

  • A box of clay contains 25 packs

Each pack is a cuboid having dimensions 10cm × 10cm × 4 cm

<h3><u>To</u><u> </u><u>Find </u><u>:</u><u>-</u><u> </u></h3>

  • <u>We have to find</u><u> </u><u>the</u><u> no of spheres of radius 6cm can Jack make from a box of clay </u><u>.</u>

<u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u>

<u>Here, we have </u>

  • Length of one pack = 10cm
  • Breath of 1 pack = 10 cm
  • Height of 1 pack = 4 cm

<u>We know that, </u>

Volume of cuboid

\bold{\red{ = length }}{\bold{\red{\times{ breath }}}}{\bold{\red{\times{height}}}}

<u>Subsitute the required values, </u>

\sf{ = 10  }{\sf{\times{ 10}}}{\sf{\times{4 }}}

\sf{ = 100  }{\sf{\times{ 4}}}

\bold{ = 400\: cm²  }

Thus, The volume of 1 pack is 400 cm²

<h3><u>Now, </u></h3>

<u>We </u><u>know </u><u>that</u><u>, </u>

Volume of sphere

\bold{\pink{ = }}{\bold{\pink{\dfrac{4}{3}}}}{\bold{\pink{\pi{r^{3}}}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ = }{\sf{\dfrac{4}{3}}}{\sf{\times{ 3.14 }}}{\sf{\times{(6)^{3}}}}

\sf{ = }{\sf{\dfrac{4}{3}}}{\sf{\times{ 3.14 }}}{\sf{\times{216}}}

\sf{ = 4}{\sf{\times{ 3.14 }}}{\sf{\times{72}}}

\sf{ = 288}{\sf{\times{ 3.14 }}}

\bold{ = 91.71 cm^{3}}

<h3><u>Therefore</u><u>, </u></h3>

No of spheres formed by 1 packs of cuboid

n = Volume of 1 packs/ Volume of sphere

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ n = }{\sf{\dfrac{ 400}{91.71}}}

\bold{ n = 4.36  }

Thus, The number of spheres formed by 1 pack of cuboid are 4.36

<h3><u>Therefore</u><u>, </u></h3>

Total number of spheres formed by 25 packs

\sf{ = 25 }{\sf{\times{ 4.36}}}

\bold{ = 109 }

Hence, The total number of spheres made by Jack from a box of clay is 109 spheres.

Vinil7 [7]2 years ago
5 0

Answer:

11 spheres

Step-by-step explanation:

hope this helps!

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