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Lesechka [4]
2 years ago
8

The 3 stages representing the hierarchy of fluency progression including Automaticity, are embedded into which strand of the B.E

.S.T. mathematics standards
Mathematics
1 answer:
Dvinal [7]2 years ago
8 0

The three stages that have to do with fluency, progression and automaticity are found in the Number Sense and Operations .

<h3>What is the number sense and operation strand of mathematics?</h3>

This is the part of mathematics that is known to teach the student basic ways to carry out number operations in mathematics. This has to do with representation of numbers as well as solving for the existing relationships in these numbers.

Having a sense of numbers is a very important ability skill that has to be developed early is students to enable them progress in the subject.

Read more on numbers and operations in mathematics here:

brainly.com/question/295961

#SPJ1

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arlik [135]

Answer:

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3 years ago
Apply the distributive property to create an equivalent expression. 6(5x - 3) =
Allushta [10]

Answer:

30x-18

Step-by-step explanation:

(6)(5x+−3)

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=30x-18

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What number completes the following equation 8× (40+7) =(8× )+(×7)
Vladimir [108]
8x( 47 ) = 8x + 7x
8x( 47 ) = 8x( 2 ) - x
8x( 47 - 2 ) = - x
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5 0
3 years ago
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Step-by-step explanation:

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7 0
2 years ago
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A conservative estimate of the number of stars in the universe is 6 x 10^22. The average human can see about 3,000 stars at nigh
Ilia_Sergeevich [38]

2 \times 10^{19} times more stars are there in universe compared to human eye can see

<h3><u>Solution:</u></h3>

Given that, conservative estimate of the number of stars in the universe is 6 \times 10^{22}

The average human can see about 3,000 stars at night with only their eyes

To find: Number of times more stars are there in the universe, compared to the stars a human can see

Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see

Then from given statement,

\text{Stars in universe} = x \times \text{ number of stars human can see}

<em><u>Substituting given values we get,</u></em>

6 \times 10^{22} = x \times 3000\\\\x = \frac{6 \times 10^{22}}{3000}\\\\x = \frac{6 \times 10^{22}}{3 \times 10^3}\\\\x = 2 \times 10^{22-3}\\\\x = 2 \times 10^{19}

Thus 2 \times 10^{19} times more stars are there in universe compared to human eye can see

5 0
3 years ago
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