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2 years ago

See attachment below

Mathematics

1 answer:

Tom [10]2 years ago

7 0

Do u have a better pic of the ?

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Help pleaseeeeeeeeeeeeee

sdas [7]

The sales tax is $632.17

6 0

3 years ago

Mr. Chen writes the expression 4 ×

telo118 [61]

Answer:

4*(7-2)2÷10

=4*5*1/5

=20/5

Step-by-step explanation:

3 0

3 years ago

What is the probability the dice sum to 8 given that both dice show even numbers?

Ber [7]

With 2 dices we have all 6x6=36 ways.
But for two conditions: sum 8 and both even numbers, we have only: (2;6), (6;2), (4;4). That's all.
And the probability is 3/36= 1/12
Have fun

7 0

4 years ago

Delta makes 12-volt car batteries. These batteries are known to be normally

blondinia [14]

Answer:

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

Step-by-step explanation:

Step(i):-

Given that the sample size n =12 -volt car batteries

Let 'X' be a Random variable in a normal distribution

Given that mean of the normal distribution = 45 months

Given that the Standard deviation of the normal distribution = 8months

Step(ii):-

Let X₁ = 3 years = 12 × 3 = 36 months

$Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{36-45}{8} = -1.125$

Let X₂ = 4 years = 12 × 4 = 48 months

$Z_{2} = \frac{x_{2} -mean}{S.D} = \frac{48-45}{8} = 0.375$

Step(iii):-

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = P(-1.125≤Z≤0.375)

= P(Z≤0.375) - P(Z≤-1.125)

= 0.5 +A(0.375) - (0.5-A(1.125)

= 0.5 + 0.1480 - (0.5 -0.3708)

= 0.1480 + 0.3708

= 0.5188

Final answer:-

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

5 0

3 years ago

a big cruise ship dropped anchor off the Caribbean island of antigua. the heavy anchor dropped into the water at a rate of 2.5 m

AysviL [449]

Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell

(2.5 m/s) x (45 s) = 112.5 meters .

If it wound up only 40 meters underwater, then it must have fallen

(112.5 m - 40 m) = 72.5 meters

from its storage position on the big cruise ship,
before it ever reached the water.

Since it was falling at the rate of 2.5 m/s, it took

(72.5 m) / (2.5 m/s) = 29 seconds

to get down to the water surface after it started dropping.

6 0

3 years ago