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cricket20 [7]
3 years ago
12

How do you simplify 5 (3t) - 7 (2t)

Mathematics
1 answer:
Vlada [557]3 years ago
7 0

Answer:

3t-2

Step-by-step explanation:

  1. Multiply the terms 3t and 2t. You should get 5t.
  2. Subtract 7 from 5; you should get -2.
  3. Now, your equation is 3t-2, you're done!
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Lindy puts £ 78 into an account which pays inrerest at a rate of 5% per anum. What will be the simple interest after 6 years .wh
Alika [10]

Answer:

Interest: £23.4

Amount: £101.4

Step-by-step explanation:

6 × 5/100 × 78 = 23.4

Balance: 78 + 23.4 = 101.4

5 0
3 years ago
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Samuel's car usually takes about 12.5 gallons of gas to fill it up when it's empty while driving through Canada Samuel notice th
nika2105 [10]

Answer: 47.4 liters

Step-by-step explanation:

From the question, we are informed that Samuel's car usually takes about 12.5 gallons of gas to fill it up when it's empty and while in Canada, he noticed that one liter is equivalent to 0.264 gallons.

The number of liters it'll take to fill Samuels car will be:

= 12.5/0.264

= 47.4 litres

7 0
3 years ago
PLEASE HELP WITH #6 and #8, DUE SOON!!
Oliga [24]

how do i answer that I don't even know that sorry

3 0
3 years ago
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Suppose y varies directly with x. if y=-3 when x=5 find y when x=-1
Scrat [10]
\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x

&&  y={{ k }}x
\end{array}
\\ \quad \\
\textit{we know that, when}
\begin{cases}
y=-3\\
x=5
\end{cases}\implies y=kx\implies (-3)=k(5)

solve for "k", to find the "constant of variation",
then plug it back in the y = kx, to get the equation
now
what's is y when x = -1?
well, just plug that in the equation with the found "k" value,
to get "y" :)
3 0
3 years ago
Read 2 more answers
what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible
zheka24 [161]

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0
2 years ago
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