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2 years ago

Will somebody please help me? I appreciate it! <3

Mathematics

2 answers:

Sati [7]2 years ago

5 0

4,7,6 you plug in the x value into x and with how the equation is set up, you divide each number by two to get your y. Do the opposite to solve for x

leonid [27]2 years ago

3 0

Answer:

4,7, and 6

Step-by-step explanation:

8 divided by 2 is 4

14 divided by 2 is 7

3 times 2 is 6

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Please someone help me I'm stuck on my homework for at least a hour

miss Akunina [59]

Pi is 3.14

1st # is 3.13

2nd # is 3.15

These numbers are irrational because pi=infinity

( I am not exactly sure if this is right so don't blame me if you get this wrong, I just tried to help.....) :T

6 0

2 years ago

Anyone know the answer?

wariber [46]

Answer:

w=51

x=0

51-0=51

y=69

z=60

69+60=129

3 0

2 years ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

Read 2 more answers

Which of the following best describes the ordered pairs listed below? (-5, 6), (3, -10), (5, -14), (10, -24)

Vlada [557]

If this is multiple choice im gonna say C

5 0

2 years ago

Cody pays $657 for six months of guitar lessons. He pays the same amount for lessons each month. Which of the following is the b

stiv31 [10]

The answer is D. $110

4 0

3 years ago