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Arada [10]
2 years ago
10

abcd is a parallelogram and ab is produced to x such that ab=bx as shown in figure. show that dx and bc bisect eachother at o.​

Mathematics
1 answer:
Annette [7]2 years ago
6 0

Answer:

is a parallelogram and ab is produced to x such that ab=bx as shown in figure. show that dx and bc bisect eachother at o.

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When using blocking to deal with extraneous factors in an experiment, the
Elena L [17]

Answer:

<em>False</em>

Step-by-step explanation:

took the test

6 0
3 years ago
The area of the city of Vancouver is 115 km^2. if the shape of Vancouver is approximately a square, how wide is the city of Vanc
Dmitry [639]

Answer:

The wide of the city is 10.7km

Step-by-step explanation:

To solve this we first have to know the formula to calculate the area of ​​a square

a = area = 115 km²

s = side

a = s * s

now we replace with the known values

115 km² = s * s

115 km² = s²

√(115 km²) = s

10.724km = s

Round to the nearest tenth

s = 10.724km = 10.7km

The wide of the city is 10.7km

5 0
3 years ago
Please explain your answer
Ymorist [56]

Answer:

51

Step-by-step explanation:

11+(-7)^2-9 - original

11+49-9 - square the -7, since its in brackets the negative applies too and a negative x a negative = positive, so it ends up as 7x7+49

60-9 - add both positives 11+49=60

51 - subtract 9 from 60, 60-9=51

7 0
3 years ago
The scale of a room in blueprint is 3in 5ft. A wall in the same blueprint is 18in. what are the actual room measurements?
QveST [7]

Answer:

Actual length of wall = 30ft

Step-by-step explanation:

We have scale of a room as 3 inch for 5ft.

We can write scaling factor as:

Scaling factor = 3 /60     (Since 5ft = 60 inches )

Scaling factor = 1/20

Now,

a wall in the blueprint is 18inch.

So actual length of wall can be determined by dividing 18 inch by the scale factor.

i.e actual length of wall = 18 / scale factor  = 18 / (1/20)

 actual length of wall = 18* 20 = 360 inch = 30ft (Since 360 inch = 30ft)

Hence Actual length of wall = 30ft

5 0
3 years ago
Solve the equation for y (y-3)^2=4y-12
Ket [755]
(y -3)^2 = 4y - 12

Expand.

(y-3)(y -3) = 4y - 12

y² - 6y + 9 = 4y - 12

y² - 6y -4y + 9 + 12 = 0

y² - 10y + 21 = 0

Factors are -7y and - 3y

y² - 10y + 21 = 0

y² - 3y - 7y + 21 = 0

y(y - 3) -7(y - 3) = 0

(y - 3)(y - 7) = 0

y-3 = 0   or    y - 7 = 0

y = 0 + 3  or  y = 0 + 7

y = 3 or 7
8 0
3 years ago
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