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makvit [3.9K]
3 years ago
14

A pet supply chain called Pet City has 5 hamsters and 10 gerbils for sale at its Lanberry location. At its Milford location, the

re are 13 hamsters and 16 gerbils. Which location has a higher ratio of hamsters to gerbils?
Mathematics
1 answer:
Vlad1618 [11]3 years ago
4 0

Answer:

Milford location has a higher ratio of hamsters to gerbils.

Step-by-step explanation:

Given:

A pet supply chain called Pet City has 5 hamsters and 10 gerbils for sale at its Lanberry location.

At its Milford location, there are 13 hamsters and 16 gerbils.

Now, to find the location who has a higher ratio of hamsters to gerbils.

Ratio of hamsters to gerbils at Lanberry location = 5:10.

=\frac{5}{10}=0.50

                                                                         

Ratio of hamsters to gerbils at Milford location= 13:16.

=\frac{13}{16} =0.8125

                                                       

<em>So, 0.8125 > 0.50.</em>

<em>Thus, </em><u><em>13:16 > 5:10.</em></u><em> </em>

Therefore, Milford location has a higher ratio of hamsters to gerbils.

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Answer:

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Step-by-step explanation:

Given

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To calculate the actual perimeter, we need to first calculate the distance between the points;

Such that:

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CD represents distance between point C and D

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Here, we consider A = (0,1); B = (3,4);

Distance is calculated as;

Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

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Substitute these values in the formula above

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AB = \sqrt{9*2}

AB = \sqrt{9}*\sqrt{2}

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Calculating BC

Here, we consider B = (3,4); C = (4,3)

Here,

(x_1,y_1) = B (3,4)

(x_2,y_2) = C(4,3)

Substitute these values in the formula above

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BC = \sqrt{1 + 1}

BC = \sqrt{2}

Calculating CD

Here, we consider C = (4,3); D = (3,0)

Here,

(x_1,y_1) = C(4,3)

(x_2,y_2) = D (3,0)

Substitute these values in the formula above

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Here, we consider C = (4,3); D = (3,0)

Here,

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Substitute these values in the formula above

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Then it is stated that it takes 5 hours or 300mins for him to go from KC - MAG, and the speed is constant.

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Here he goes 36 mi at constant speed (x), then picks up his speed by 3 km/hour (x+3).

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He reaches to KC, 15 mins earlier than KC - MAG, so he reaches there in 4.75 hours or in 275 min.

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