Answer:
Step-by-step explanation:
Given points moves b/w 0.1 of 0.3 marks Hence amplitude is 0.2
Also , frequency (w) = 100 rad/s.
Natural frequency (wn) = √K/m
K = 20 N/mm x 1000mm/1m = 20000N/M
W = 1000mm/1m = 20,000N/M
FormulaX = FolK/1 - (w/wn)²
0.2 = b/20000/1 - (100/50)²
Given forcing frequency was doubled, W1 = 2 x 100=200rad/s
X1 =b/20,000/1 - (200/20)²
0.2/11 = 1 - (200/50)²/1 - (100/50)² = 0.2/11 = -15^5– 3
X1 = 0.04
2*8 using <span>distributive property
= 2(3+5)
= 6+ 10
= 16</span>
Answer:
150 degrees
Step-by-step explanation:
Let's start off by looking at what we are working with in this specific problem:
We can see that we are looking at 2 angles, angle L and angle M, that add up to a total of 180 degrees (aka a straight line)
Now that we know that, we also have to keep is mind that angle L + angle M = 180 degrees.
Now that we've got all of that out of the way, let's set up a simple algebraic equation:
angle L + angle M = 180
We also know that angle L is 30 degrees so let's add it into the equation we have just created:
30 + angle M = 180
We now know that 30 plus angle M (whatever it might be) is equal to 180 so in order to solve this problem we have to do some simple subtraction.
180 - 30 = angle M
Now we are left with:
150 degrees = angle M
The problem 10bf + 25bg – 21p – 14pq cannot be factored because it cannot be simplifed further. This is because there are no common factors between in any of the terms.
Multiply 7 by 9 and you will get 63 which is x.