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Lyrx [107]
2 years ago
10

Answer for brainliest please

Mathematics
1 answer:
labwork [276]2 years ago
4 0

Step-by-step explanation:

example: the distance form the line y=x till Y and Y' must be the same

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1/11 as a decimal rounded to three decimal places
Ber [7]

In order to determine 1/11 as a decimal you need to divide 1 by 11. This would equal 0.0909090909090909. Rounding this number to three decimal places would equal 0.091.

6 0
2 years ago
Can someone help me with this question?
sesenic [268]

Answer:

One of the angles in the triangle might be 50.

AND

The length of the third side must be 11cm or smaller.

Step-by-step explanation:

-The triangle might be an equilateral triangle (having all the same sides and angles). False, since the triangle sum theorem states that all angles inside of a triangle must add up to 180, so an equilateral triangle would need to have all three angles at 60 degrees.

-One of the angles in the triangle must be 120 (false; it can be anything above 90, which is not only 120)

-The length of the third side must be 11cm or smaller. (True, Triangle Inequality Theorem)

-One of the angles in the triangle might be 50 (possibly, so very much true)

3 0
2 years ago
Find the length of the base of a square pyramid if the volume is 128 cubic inches and has a height of 6 inches
Len [333]

Answer: a = 8

Step-by-step explanation:

Volume of a square based pyramid is given as

\frac{a^{2}h }{3} .

where a is the length of the side and h is the height.

Substituting into the formula , we have

V = \frac{a^{2}h }{3}

128 = a^{2}h /3

384= a^{2} X 6

Divide through by 6

384/6 = a^{2}

64 = a^{2}

Therefore :

a = \sqrt{\frac{64}{1} }

a = 8

6 0
3 years ago
Sare sold in packs and boxes.
Hoochie [10]

Answer:

derivative n thof \: sin2x

5 0
2 years ago
Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap
bazaltina [42]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)

A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

<em>The circumference of a quarter of circle is equal to</em>

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)

C=6\pi\ cm

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

AC=\sqrt{12^2+12^2}

AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

6 0
3 years ago
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