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vlabodo [156]
3 years ago
12

Help me solve this please

Mathematics
1 answer:
Anna71 [15]3 years ago
8 0
27+ 2/5×-1/2 = 27 - 1/5
(135 - 1)/5 = 134 /5 <——answer
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In the algebraic expression v+8 the v is considered the what
chubhunter [2.5K]

Answer:

the variable  

Step-by-step explanation:

5 0
3 years ago
What is P-6 equal.
katovenus [111]

Answer:

Step-by-step explanation:

P-6 is an expression, your question is incomplete.

6 0
3 years ago
What is the following sum? Assume x20 and 20.<br> √√x²y³ +2√√x³y² + xy √√y
max2010maxim [7]

The value of the expression \sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y is 2xy\sqrt{y} + 2xy^2\sqrt{x}

<h3>How to evaluate the sum?</h3>

The attachment represents the proper format of the question

The summation expression is given as:

\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y

Expand the radicands

\sqrt{x^2y^2 * y} + 2\sqrt{x^2y^4* x} + xy\sqrt y

Evaluate the square roots

xy\sqrt{y} + 2xy^2\sqrt{x} + xy\sqrt y

Add the like terms

2xy\sqrt{y} + 2xy^2\sqrt{x}

Hence, the value of the expression \sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y is 2xy\sqrt{y} + 2xy^2\sqrt{x}

Read more about expressions at:

brainly.com/question/723406

#SPJ1

3 0
2 years ago
A 4-pack of greeting cards costs $7.40. What is the unit price?pls answer fast
densk [106]

Answer:

The unit price of the problem is that one pack of greeting cards costs $1.85

Step-by-step explanation:

In order to find the unit rate, you have to divide the price by the quantity of the product. So, we will divide 7.40 by 4 so we can see the price of one pack.

7.40 ÷ 4 = 1.85

So, one pack of greeting cards costs $1.85 which is also our unit price.

3 0
3 years ago
Susan needs material for her school project. She buys 3.75 yards of material at $5.72 a yard. What is the total cost of the mate
elena55 [62]

Answer: $21.45

Step-by-step explanation:

FACTS:

1 yard costs $5.72.

She bought 3.75 yards

Total cost= cost per yard x number of yards

Total: t

t= 5.72x3.75

t= $21.45

She spent $21.45 for 3.75 yards of material

8 0
2 years ago
Read 2 more answers
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