the √8=2.82842712
so 2.82842712*2.82842712=8
Answer:
This is the correct way to set up the equation:
9x + 88 + 6x + 182 = 180
I'm going to move some things around so we can combine like terms. It now reads:
9x + 6x + 88 + 182 = 180
9x + 6x = 15x, so the equation now reads:
15x + 88 + 182 = 180
88 + 182 = 270, so the equation reads:
15x + 270 = 180
Subtract the 270 from both sides. 180 - 270 is -90:
15x = -90
Divide both sides by 15. -90 divided by 15 = -6:
x = -6
Now we can substitute -6 back into the separate equations.
9(-6) + 88 = ?
9 times -6 is -54. -54 + 88 = 34.
6(-6) + 182 = ?
6 times -6 = -36. -36 + 182 = 146
Now we can add 34 and 146 together.
34 + 146 = 180
I hope I helped answer your question!
Step-by-step explanation:
Answer:
- x +y = 500
- 0.65x +0.95y = 0.75(500)
- solution: (x, y) = (300, 200)
Step-by-step explanation:
A system of equations for the problem can be written using the two given relationships between quantities of brass alloys.
<h3>Setup</h3>
Let x and y represent the quantities in grams of the 65% and 90% alloys used, respectively. There are two relations given in the problem statement.
x + y = 500 . . . . . . quantity of new alloy needed
0.65x +0.90y = 0.75(500) . . . . . quantity of copper in the new alloy
These are the desired system of equations.
<h3>Solution</h3>
This problem does not ask for the solution, but it is easily found using substitution for x.
x = 500 -y
0.65(500 -y) +0.90y = 0.75(500)
(0.90 -0.65)y = 500(0.75 -0.65) . . . . . . subtract 0.65(500)
y = 500(0.10/0.25) = 200
x = 500 -200 = 300
300 grams of 65% copper and 200 grams of 90% copper are needed.
The answer is 26 because if you round 12.5 it would be 13 and of you would round 1.75 it would be 2. After you do this you would multiply the 2 numbers and get 26 which is your answer.
