Answer:
There's no picture for us to refer to. I need a picture to answer the question.
When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.
The first factor is x - (a + √b).
The second factor is x - (a - √b).
The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
= x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
= x² - 2ax + x√b - x√b + a² - b
= x² - 2ax + a² - b
This is a quadratic polynomial, as expected.
If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
= a +/- (1/2)*√(4b)
= a +/- √b
x = a + √b, or x = a - √b, as expected.
Yo sup??
area of trapezium=1/2*sum of opposite sides* height of trapezium
=1/2*44*13
=22*13
=286 sq units
Hope this helps
Hey there! :D
99%=.99
100*.99= 99
100+99= 199
So, you would be correct. 99% of 100= 99 Nice work!
I hope this helps!
~kaikers
Answer:
66
Step-by-step explanation:
