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11Alexandr11 [23.1K]
2 years ago
5

Complete: A line drawn from a centre of a circle ________the chord, then the line is_________​

Mathematics
2 answers:
lys-0071 [83]2 years ago
7 0

Answer:

Complete: A line drawn from a centre of a circle to the midpoint of the chord, then the line is perpendicular

Reptile [31]2 years ago
4 0

hi

A line drawn from the centre of a circle to a chord always bisects it

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G(x)= 3x-5<br> h(x)=2/2x+3<br> write h(g(x)) as an expression terms of x
andreev551 [17]

Answer: h(g(x))= 2/6x-7

Step-by-step explanation:

1.h(g(x))= 2/(g(x))+3

2.g(x)= 3x-5

h(g(x))= 2/2(3x-5)+3

=2/6x-10+3

=2/6x-7

7 0
3 years ago
A store can buy 8 cartons of milk for 24 dollars or 7 cartons of milk for $28.
larisa86 [58]

Answer:

a

Step-by-step explanation:

28/7=4

24/8=3

8 0
2 years ago
Someone please help me!!!!
kondaur [170]

Answer:

9.5

Step-by-step explanation:

13x+1+12x-2+14x+1+109+132+128

collect all the like terms

13x+12x+14x

=39x

1+-2+1+109+132+128

=369

39x=369

divide both sides by 39

=9.5

8 0
3 years ago
Given f(x)=2x^2+3x-5 for what values of x is f(x) positive
kow [346]

Answer:

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

Step-by-step explanation:

we have

f(x)=2x^{2}+3x-5

This is a vertical parabola open upward (the leading coefficient is positive)

The vertex is a minimum

The coordinates of the vertex is the point (h,k)

step 1

Find the vertex of the quadratic function

Factor the leading coefficient 2

f(x)=2(x^{2}+\frac{3}{2}x)-5

Complete the square

f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-5-\frac{9}{8}

f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-\frac{49}{8}

Rewrite as perfect squares

f(x)=2(x+\frac{3}{4})^{2}-\frac{49}{8}

The vertex is the point (-\frac{3}{4},-\frac{49}{8})

step 2

Find the x-intercepts (values of x when the value of f(x) is equal to zero)

For f(x)=0

2(x+\frac{3}{4})^{2}-\frac{49}{8}=0

2(x+\frac{3}{4})^{2}=\frac{49}{8}

(x+\frac{3}{4})^{2}=\frac{49}{16}

take the square root both sides

x+\frac{3}{4}=\pm\frac{7}{4}

x=-\frac{3}{4}\pm\frac{7}{4}

x_1=-\frac{3}{4}+\frac{7}{4}=1

x_2=-\frac{3}{4}-\frac{7}{4}=-2.5

therefore

The function f(x) is negative in the interval (-2.5,1)

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

see the attached figure to better understand the problem

6 0
4 years ago
Plz help i am stuck and close to getting my a33 beat
krek1111 [17]

Answer:

oof leeme find it

Step-by-step explanation:

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3 years ago
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