Note that c is the hypotenuse of the blue triangle, and that the Pyth. Thm. states that (length of one leg)^2 + (length of the other leg)^2 = (hyp)^2.
Therefore, (hyp)^2 = c^2 = [2sqrt(x^2+3x)]^2 + 3^2, or
= 4(x^2+3x) + 9, or
= 4x^2 + 12x + 9 = (2x+3)^2
Taking the sqrt of both sides, c = plus or minus (2x+3). Eliminate -(2x+3) because the middle term of the square of this would be negative, in conflict with the given +12x.
c=2x+3 is the correct answer.
Answer:
DK = 9
Step-by-step explanation:
In triangle AMD,
h² = p² + b²
or, h² = 6² + 4²
or, h²= 36 + 16
so, h² = 52
so, AM² = 52
Take x as reference angle,
cos²x = 16/52
Now,
In triangle, AMK,
Taking x as reference angle,
cos²x = b²/h²
cos²x = AM²/MK²
or, cos²x = 52/MK²
Now,
cos²x = 16/52 = 52/MK²
or,
16/52 = 52/MK²
or, 16MK² = 2704
or, MK² = 2704/16
or, MK² = 169
so, MK = 13
Now,
DK = MK - MD
or, DK = 13 - 4
so, DK = 9
2-5/8-6/8=16/8-5/8-6/8=5/8 pizza slices left
3/8+7/8=10/8=1 2/8 pizza slices altogether
hope it helps:))
Answer:
1. 30
2. 150
Step-by-step explanation:

Lets assume tan(x) = u

Now we solve for 'u'
add 1 on both sides
, divide both sides by 3

Take square root on both sides

We replace tan(x) for 'u'
x = 30 because
in first quadrant
x = 30 (tan is positive in first quadrant)
x = 150 because
in second quadrant
tan is negative in second quadrant